model 7 marks scored in examinations Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11 [SSC Constable 2013]

In an examination 80% of the boys passed in English and 85% passed in Mathematics, while 75% passed in both. If 45 boys failed in both, the number of boys who sat for the examination was

a) 200

b) 450

c) 150

d) 400

Answer: (b)

Successful boys in English or Maths or both

= 80 + 85 – 75 = 90%

Unsuccessful boys = 10%

Total number of boys = $100/10 × 45$ = 450

Question : 12 [SSC CHSL 2013]

In the annual examination Mahuya got 10% less marks than Supriyo in Mathematics. Mahuya got 81 marks. The marks of Supriyo are

a) 88

b) 87

c) 89

d) 90

Answer: (d)

Let marks obtained by Supriyo = x

${9x}/10 = 81 ⇒ x = {81 × 10}/9 = 90$

Question : 13

In an examination 34% failed in Mathematics and 42% failed in English. If 20% failed in both the subjects, the percentage of students who passed in both subjects was

a) 44%

b) 50%

c) 56%

d) 54%

Answer: (a)

Let total number of students = 100

Number of failures in Maths = 34

Number of failures in English = 42

Number of failures in both subjects = 20

Number of failures in Maths or English or both

= 34 + 42 – 20 = 56

Number of students who passed in both subjects

= 100 – 56 = 44

The required percentage = 44%

Using Rule 23,

a = 34%, b = 42%, c = 20%

Passed candidates in both the subjects

= 100 – (a + b – c)

= 100 – (34 + 42 – 20) = 100 – 56 = 44%

Question : 14

In an examination a candidate must secure 40% marks to pass. A candidate, who gets 220 marks, fails by 20 marks. What are the maximum marks for the examination?

a) 600

b) 800

c) 450

d) 1200

Answer: (a)

According to question,

40% ⇒ 220 + 20 or 40% ⇒ 240

100% ⇒ $240/40 × 100 = 600$

Using Rule 24,

a = 40%, b = 220, c = 20

Total Marks = ${100(220 +20)}/40$

=${100 × 240}/40 = 600$

Question : 15 [SSC MTS 2011]

In an examination, 1100 boys and 900 girls appeared. 50% of the boys and 40% of the girls passed the examination. The percentage of candidates who failed

a) 50%

b) 45.5%

c) 54·5%

d) 45%

Answer: (c)

Failed candidates = ${1100 × 50}/100 + {900 × 60}/100$

= 550 + 540 = 1090

Required percentage = $1090/2000 × 100 = 54.5%$

Using Rule 25,

B = 1100, b = 50%, G = 900, g = 40%

Percentage of failed candidates = ${(Bb + Gg)}/{B + G}%$

= ${1100 × 50 + 900 × 40}/{1100 + 900}$

= ${55000 + 36000}/2000$

= $91/2$ = 45.5%

IMPORTANT quantitative aptitude EXERCISES

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