Model 1 Basic Time & Distance using formula Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CHSL 2012]

A train starts from a place A at 6 a.m. and arrives at another place B at 4.30 p.m. on the same day. If the speed of the train is 40 km per hour, find the distance travelled by the train ?

a) 400 km

b) 320 km

c) 230 km

d) 420 km

Answer: (d)

Using Rule 1,

Time = 10$1/2$ hours = $21/2$ hours

Speed = 40 kmph

Distance = Speed × Time

= $40 × 21/2$ = 420 km

Question : 2 [SSC CGL Prelim 2005]

A man riding his bicycle covers 150 metres in 25 seconds. What is his speed in km per hour ?

a) 20

b) 23

c) 21.6

d) 25

Answer: (b)

Using Rule 1,

Speed = $150/25$ = 6 m/sec

= $6 × 18/5 = 108/5$ = 21.6 kmph

Question : 3 [SSC CHSL 2012]

Two men start together to walk a certain distance, one at 4 km/h and another at 3 km/h. The former arrives half an hour before the latter. Find the distance.

a) 9 km

b) 6 km

c) 7 km

d) 8 km

Answer: (c)

If the required distance be x km, then

$x/3 - x/4 = 1/2$

${4x - 3x}/12 = 1/2$

$x/12 = 1/2$ ⇒ x = 6 km

Using Rule 9,

Here $S_1 = 4, t_1 = x, S_2 = 3, t_2 = x + 1/2$

$S_1t_1 = S_2t_2$

$4 × x = 3(x + 1/2)$

$4x - 3x = 3/2 x = 3/2$

Distance= $4 × 3/2$ = 6 kms

Question : 4 [SSC MTS 2013]

A train covers a certain distance in 210 minutes at a speed of 60 kmph. The time taken by the train, to cover the same distance at a speed of 80 kmph is :

a) 3 hours

b) 4$5/8$ hours

c) 2$5/8$ hours

d) 3$5/8$ hours

Answer: (b)

Speed of train = 60 kmph

Time = 210 minutes

= $210/60$ hours or $7/2$ hours

Distance covered

= $60 × 7/2$ = 210 km

Time taken at 80 kmph

= $210/80 = 21/8$ hours

= 2$5/8$ hours

Using Rule 9,

Here, $S_1 = 60, t_1 = 210/60 hrs, S_2 = 80, t_2$ = ?

$S_1t_1 = S_2t_2$

60 × $210/60 = 80 × t_2$

$t_2 = 21/8$ hrs = 2$5/8$ hrs

Question : 5 [SSC CGL Prelim 2002]

An athlete runs 200 metres race in 24 seconds. His speed (in km/ hr) is :

a) 30

b) 28.5

c) 24

d) 20

Answer: (a)

Using Rule 1,

Speed = $\text"Distance"/\text"Time"$

= $200/24$ m/s

$200/24$ m/s = $200/24 × 18/5$

= 30 km/h [Since, x m/s = $18/5$ x km/h]

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