Model 1 Basic Time & Distance using formula Practice Questions Answers Test with Solutions & More Shortcuts
time & distance PRACTICE TEST [5  EXERCISES]
Model 1 Basic Time & Distance using formula
Model 2 Vehicles in x/y of its usual speed
Model 3 Problems on average speed
Model 4 Time & Distance with Ratios
Model 5 Problems with Races
Question : 1 [SSC CHSL 2012]
A train starts from a place A at 6 a.m. and arrives at another place B at 4.30 p.m. on the same day. If the speed of the train is 40 km per hour, find the distance travelled by the train ?
a) 400 km
b) 320 km
c) 230 km
d) 420 km
Answer »Answer: (d)
Using Rule 1,
Time = 10$1/2$ hours = $21/2$ hours
Speed = 40 kmph
Distance = Speed × Time
= $40 × 21/2$ = 420 km
Question : 2 [SSC CGL Prelim 2005]
A man riding his bicycle covers 150 metres in 25 seconds. What is his speed in km per hour ?
a) 20
b) 23
c) 21.6
d) 25
Answer »Answer: (b)
Using Rule 1,
Speed = $150/25$ = 6 m/sec
= $6 × 18/5 = 108/5$ = 21.6 kmph
Question : 3 [SSC CHSL 2012]
Two men start together to walk a certain distance, one at 4 km/h and another at 3 km/h. The former arrives half an hour before the latter. Find the distance.
a) 9 km
b) 6 km
c) 7 km
d) 8 km
Answer »Answer: (c)
If the required distance be x km, then
$x/3  x/4 = 1/2$
${4x  3x}/12 = 1/2$
$x/12 = 1/2$ ⇒ x = 6 km
Using Rule 9,
Here $S_1 = 4, t_1 = x, S_2 = 3, t_2 = x + 1/2$
$S_1t_1 = S_2t_2$
$4 × x = 3(x + 1/2)$
$4x  3x = 3/2 x = 3/2$
Distance= $4 × 3/2$ = 6 kms
Question : 4 [SSC MTS 2013]
A train covers a certain distance in 210 minutes at a speed of 60 kmph. The time taken by the train, to cover the same distance at a speed of 80 kmph is :
a) 3 hours
b) 4$5/8$ hours
c) 2$5/8$ hours
d) 3$5/8$ hours
Answer »Answer: (b)
Speed of train = 60 kmph
Time = 210 minutes
= $210/60$ hours or $7/2$ hours
Distance covered
= $60 × 7/2$ = 210 km
Time taken at 80 kmph
= $210/80 = 21/8$ hours
= 2$5/8$ hours
Using Rule 9,
Here, $S_1 = 60, t_1 = 210/60 hrs, S_2 = 80, t_2$ = ?
$S_1t_1 = S_2t_2$
60 × $210/60 = 80 × t_2$
$t_2 = 21/8$ hrs = 2$5/8$ hrs
Question : 5 [SSC CGL Prelim 2002]
An athlete runs 200 metres race in 24 seconds. His speed (in km/ hr) is :
a) 30
b) 28.5
c) 24
d) 20
Answer »Answer: (a)
Using Rule 1,
Speed = $\text"Distance"/\text"Time"$
= $200/24$ m/s
$200/24$ m/s = $200/24 × 18/5$
= 30 km/h [Since, x m/s = $18/5$ x km/h]
IMPORTANT quantitative aptitude EXERCISES
Model 1 Basic Time & Distance using formula Shortcuts »
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Model 1 Basic Time & Distance using formula
Defination & Shortcuts … 
Model 2 Vehicles in x/y of its usual speed
Defination & Shortcuts … 
Model 3 Problems on average speed
Defination & Shortcuts … 
Model 4 Time & Distance with Ratios
Defination & Shortcuts … 
Model 5 Problems with Races
Defination & Shortcuts …
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