Model 10 Percentage With Allegations & Mixture Practice Questions Answers Test With Solutions & More Shortcuts
PERCENTAGE PRACTICE TEST [11 - EXERCISES]
Model 1 Simple Percentage Questions
Model 2 Net Increase Or Decrease In %
Model 3 Reducing & Exceeding Prices
Model 4 X & Y Comparison
Model 5 Income & Expenditure
Model 6 Consumption & Remaining
Model 7 Marks Scored In Examinations
Model 8 Population Based
Model 9 Voters & Election
Model 10 Percentage With Allegations & Mixture
Model 11 Percentage With Ratios
Question : 1 [SSC SO 2007]
200 litres of a mixture contains 15% water and the rest is milk. The amount of milk that must be added so that the resulting mixture contains 87.5% milk is
a) 45 litres
b) 30 litres
c) 35 litres
d) 40 litres
Answer »Answer: (d)
In 200 litres of mixture,
Quantity of milk = 85 100 ´ 200 = 170 litres
Quantity of water = 30 litres
Let the quantity of additional milk added be x litres.
According to the question,
${170 + x}/{200 + x} × 100 = 87.5$
(170 +x) × 100 = 17500 + 87.5x
100x – 87.5x = 17500 – 17000
12.5x = 500
x = $500/12.5$ = 40 litres
Question : 2 [SSC CGL Tier-I 2014]
In what ratio must 25% of alcohol be mixed with 50% of alcohol to get a mixture of 40% strength alcohol ?
a) 3 : 2
b) 1 : 2
c) 2 : 1
d) 2 : 3
Answer »Answer: (d)
Required ratio = $1/10 : 3/20 = 2 : 3$
Question : 3 [SSCCHSL 2011]
75 gm of sugar solution has 30% sugar in it. Then the quantity of sugar that should be added to the solution to make the quantity of the sugar 70% in the solution, is
a) 130 gm
b) 125 gm
c) 100 gm
d) 120 gm
Answer »Answer: (c)
Sugar in original solution
= ${75 × 30}/100$ = 22.5gm
Let x gm of sugar be mixed.
${22.5 + x}/{75 + x} × 100 = 70$
2250 + 100x = 75 × 70 + 70x
2250 + 100x = 5250 + 70x
30x = 5250 – 2250 = 3000
x = $3000/30$ = 100 gm
Question : 4 [SSC CGL Tier-II 2015]
300 grams of sugar solution has 40% of sugar in it. How much sugar should be added to make it 50% in the solution?
a) 80 gram
b) 40 gram
c) 10 gram
d) 60 gram
Answer »Answer: (d)
In 300 gm of solution,
Sugar = ${300 × 40}/100 = 120gm.$
Let x gm of sugar be mixed.
According to the question,
${120 + x}/{300 + x} =1/2$
240 + 2x = 300 + x
2x – x = 300 – 240 ⇒ x = 60 gm.
Question : 5
How much water must be added to 100 ml of 80 per cent solution of boric acid to reduce it to a 50 per cent solution ?
a) 60 ml
b) 30 ml
c) 40 ml
d) 50 ml
Answer »Answer: (a)
Let x ml of water be added.
${20 + x}/{100 + x} × 100$ = 50
40 + 2x = 100 + x ⇒ x = 60 ml
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Model 10 Percentage With Allegations & Mixture Shortcuts »
Click to Read...Model 10 Percentage With Allegations & Mixture Online Quiz
Click to Start..PERCENTAGE SHORTCUTS AND TECHNIQUES WITH EXAMPLES
-
Model 1 Simple Percentage Questions
Defination & Shortcuts … -
Model 2 Net Increase Or Decrease In %
Defination & Shortcuts … -
Model 3 Reducing & Exceeding Prices
Defination & Shortcuts … -
Model 4 X & Y Comparison
Defination & Shortcuts … -
Model 5 Income & Expenditure
Defination & Shortcuts … -
Model 6 Consumption & Remaining
Defination & Shortcuts … -
Model 7 Marks Scored In Examinations
Defination & Shortcuts … -
Model 8 Population Based
Defination & Shortcuts … -
Model 9 Voters & Election
Defination & Shortcuts … -
Model 10 Percentage With Allegations & Mixture
Defination & Shortcuts … -
Model 11 Percentage With Ratios
Defination & Shortcuts …
QUANTITATIVE APTITUDE CATEGORIES
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» Number System
-
» Average
-
» LCM & HCF
-
» Percentage
-
» Profit & Loss
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» Time & Work
-
» Pipes & Cisterns
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» Time & Distance
-
» Trains
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» Compound Interest
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» Simplification
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» Discount
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» Power
-
» Permutations & Combination
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» Ratio & Proportion
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» Advance Math
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» Algebraic Expressions
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» Trigonometric Ratios & Identities
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» Simple Interest
-
» Alligation & Mixtures
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» Boats & Streams
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» Set Theory
-
» Linear Equations
-
» Quadratic Equations
-
» Mensuration
-
» Squareroots & Cuberoots
-
» Data Sufficiency
-
» Logarithm
-
» Probability
-
» Statistics
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