# Model 3 Reducing & Exceeding Prices Practice Questions Answers Test With Solutions & More Shortcuts

#### PERCENTAGE PRACTICE TEST [11 - EXERCISES]

Question : 1 [SSC Constable 2012]|||

A number, on subtracting 15 from it, reduces to its 80%. What is 40% of the number?

a) 75

b) 30

c) 90

d) 60

If the number be x, then

x – 15 = \${4x}/5\$

5x – 75 = 4x ⇒ x = 75

40% of 75 = \${75 × 40}/100 = 30\$

Question : 2 [SSC CGL Tier-II 2015]|||

A reduction of 20% in the price of sugar enables a purchaser to obtain 8 kg more for Rs.160. Then the price per kg before reduction was

a) Rs.5

b) Rs.10

c) Rs.4

d) Rs.6

Let the original price of sugar be Rs. x per kg.

Reduced price = Rs. \${80x}/100 = Rs.{4x}/5\$ per kg.

According to the question,

\$160/{{4x}/5} - 160/x\$ = 8

\${40 × 5}/x - 160/x = 8\$

\$200/x - 160/x = 8\$

\$40/x = 8 ⇒ 8x = 40 ⇒ x = 40/8 = 5\$ per kg.

Reduced Price = \${4x}/5 = {4 × 5}/5\$ = Rs. 4 per kg

Using Rule 31,

Reduced price per kg. = \${21 × 160}/{100 × 8}\$ = Rs. 4

Question : 3 [SSC CGL Tier-I 2015]|||

The price of an item was increased by 10%. This reduced the monthly total sales by 20%. The overall effect on the value of monthly sales is a

a) 10% increase

b) 12% increase

c) 12% decrease

d) 10% decrease

Required percentage change

= \$(10 - 20 + {10 × (-20)}/100)\$%

= –12% Negative sign shows decrease.

Using Rule 4,

If a number is increased by a% and then it is decreased by b%, then resultant change in percentage will be \$(a - b - {ab}/100)\$% (Negative for decrease, Positive for increase)

Required percentage = \$(10 - 20 - {10 × 20}/100)\$

= (–10 – 2) = 12% decrease.

Question : 4

The salary of a person is reduced by 20%. To restore the previous salary, his present salary is to be increased by

a) 20%

b) 17.5%

c) 22.5%

d) 25%

Required percentage increase = \$x/{100 - x} × 100\$

= \$(20/{100 - 20}) × 100 = 20/80 × 100 = 25%\$

Question : 5

Due to a price hike of 20%, 4 kg. less sugar is available for Rs. 120. What is the initial price per kg of sugar ?

a) Rs.5 per kg.

b) Rs.6 per kg.

c) Rs.5.5 per kg.

d) Rs.4 per kg.

Original price of sugar = Rs. x/kg. (let)

New price = Rs.\${120x}/100\$ per kg.

= Rs.\${6x}/5\$ per kg.

According to the question,

\$120/x - 120/{{6x}/5} = 4\$

\$120/x - {120 × 5}/{6x}\$ = 4

\$120/x - 100/x\$ = 4

\$30/x - 25/x\$ = 1

\$5/x\$ = 1 ⇒ x = Rs.5 per kg.

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