Model 4 X & Y Comparison Practice Questions Answers Test With Solutions & More Shortcuts

Question : 1

A's salary is 50% more than that of B. Then B's salary is less than that of A by

a) 33$1/4$%

b) 50%

c) 44$1/2$%

d) 33$1/3$%

Answer: (d)

Required percent = $(r/{100 + r} × 100)$%

= $50/{100 + 50}× 100 = 100/3 = 33{1}/3$%

Question : 2 [SSC SAS 2010]

Two numbers are less than a third number by 30% and 37% respectively. The per cent by which the second number is less than the first is

a) 4%

b) 10%

c) 3%

d) 7%

Answer: (b)

Third number = 100

First number = 70

Second number = 63

Required percentage = $7/70 × 100$ = 10

Question : 3 [SSC CPO S.I.2003]

Two numbers are respectively 12$1/2$% and 25% more than a third number. The first number as percentage of second number is

a) 75

b) 50

c) 90

d) 60

Answer: (c)

If the third number is 100, then the numbers are $100 + 25/2 = 225/2$ and 125 respectively.

First number as a percentage of the second = $225/{2×125}×100$ = 90

Using Rule 30,

If two numbers are respectively x% and y% more than a third number the first as a per cent of second is ${100 + x}/{100 + y}$ ×100%

Question : 4 [SSC MTS 2013]

A number when reduced by 10% gives 30. The number is

a) 40

b) 33$1/2$

c) 35

d) 33$1/3$

Answer: (d)

Let the number be x

then, $x × 90/100 = 30$

$x = 3000/90 = 100/3= 33{1}/3$

Question : 5

If the salary of Manoj is 40% less than that of Subhash, then by how much percentage is the salary of Subhash more than that of Manoj?

a) 66$2/3$%

b) 60%

c) 65%

d) 66$1/4$%

Answer: (a)

Required percent = $40/{100 - 40} × 100$

= ${40×100}/60 = 200/3 = 66{2}/3$%

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PERCENTAGE SHORTCUTS AND TECHNIQUES WITH EXAMPLES
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