model 7 marks scored in examinations Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CGL Prelim 2004]

In a group of students, 70% can speak English and 65% can speak Hindi. If 27% of the students can speak none of the the two languages, then what per cent of the group can speak both the languages ?

a) 28%

b) 62%

c) 23%

d) 38%

Answer: (b)

Let total number of students = 100

27 students speak none of the two languages.

It means only 73 students speak either Hindi or English or both.

Let x students speak both languages.

∴ 73 = 70 – x + x + 65 – x

x = 70 + 65 – 73 = 62%

Question : 2 [SSC CGL Prelim 2003]

A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are

a) 100

b) 120

c) 180

d) 150

Answer: (b)

Difference of percentage = (40 – 30)% = 10%

Difference of marks = 6 + 6= 12

Since,10% of total marks = 12

Total marks = ${12 × 100}/10 = 120$

Using Rule 22,

Here, m = 30%, n = 40%, p = 6, q = 6.

Maximum Marks = $100/{(n - m)} × (p + q)$

= $100/{(40 - 30)} × (6 + 6)$

= $100/10 × 12 = 120$

Question : 3

In an examination, there were 1000 boys and 800 girls. 60% of the boys and 50% of the girls passed. Find the percent of the candidates failed ?

a) 44.4%

b) 48.4%

c) 49.6%

d) 46.4%

Answer: (a)

Total candidates = 1000 + 800 = 1800

The candidates who are passed

= $1000 × 60/100 + 800 × 50/100$

= 600 + 400 = 1000

The number of candidates who failed = 1800 – 1000 = 800

Required percent = $800/1800 × 100 = 44.4%$

Using Rule 25,

Percentage of passed students = $({B.b + G.g}/{B + G})%$

= ${1000 × 60 + 800 × 50}/{1000 + 800}$

= ${60000 + 40000}/1800$

= $100000/1800 = 500/9 = 55.5$

Percentage of failed students = 100 – 55.5 = 44.4%

Question : 4 [SSC CPO S.I.2003]

A student has to obtain 33% of total marks to pass. He got 25% of total marks and failed by 40 marks. The number of total marks is

a) 500

b) 300

c) 1000

d) 800

Answer: (a)

Let the total marks be x.

According to the question,

25% of x + 40 = 33% of x

(33 – 25)% of x = 40

8% of x = 40

x = ${40 × 100}/8$ = 500

Question : 5

For an examination it is required to get 36 % of maximum marks to pass. A student got 113 marks and failed by 85 marks. The maximum marks for the examination are :

a) 565

b) 550

c) 620

d) 500

Answer: (b)

Let maximum marks be x, then,

${36 × x}/100 = 113 + 85 = 198$

$x = {198 × 100}/36 = 550$

Using Rule 24,

a = 36%, b = 113, c = 85

Maximum marks = ${(b + c)}/a × 100$

= ${(113 + 85)}/36 × 100$

= $198/36 × 100$ = 550

IMPORTANT quantitative aptitude EXERCISES

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