Model 1 Basic Pipes & Cisterns Problems Practice Questions Answers Test With Solutions & More Shortcuts
PIPES & CISTERNS PRACTICE TEST [3  EXERCISES]
Model 1 Basic Pipes & Cisterns Problems
Model 2 Filling Tank By Parts Or Fractions
Model 3 Opening Both Taps And Leaks
Question : 1 [SSC CGL TierI 2015]
A pipe can fill a tank in x hours and another can empty it in y hours. They can together fill it in (y > x)
a) ${xy}/{x  y}$ hours
b) ${xy}/{y  x}$ hours
c) x  y hours
d) y  x hours
Answer »Answer: (b)
When both pipes are opened simultaneously,
part of the tank filled in 1 hour
= $1/x  1/y = {y  x}/{xy}$
Required time = ${xy}/{y  x}$ hours
Question : 2 [SSC CGL Prelim 2003]
Two pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 minutes. In how much time the third pipe alone can empty the cistern?
a) 90 minutes
b) 110 minutes
c) 100 minutes
d) 120 minutes
Answer »Answer: (c)
Using Rule 2,
If x, y, z, ........... all taps are opened together then, the time required to fill/empty the tank will be:
$1/x ± 1/y ± 1/z ± ... = 1/T$
Where T, is the required time
Note: Positive result shows that the tank is filling and Negative result shows that the tank is getting empty.
Let the third pipe empty the cistern in x minutes.
Part of cistern filled in 1 minute when all three pipes are opened simultaneously
= $1/60 + 1/75  1/x$
According to the question,
$1/60 + 1/75  1/x =1/50$
$1/x = 1/60 + 1/75  1/50$
= ${5 + 4  6}/300 = 3/300 ⇒ 1/x = 3/300$
$x = 300/3$ = 100 minutes
Question : 3 [SSC DEO 2009]
Two pipes can fill a cistern separately in 10 hours and 15 hours. They can together fill the cistern in
a) 9 hours
b) 6 hours
c) 7 hours
d) 8 hours
Answer »Answer: (b)
Using Rule 1,
Part of the cistern filled by both pipes in 1 hour
= $1/10 + 1/15 = {3 + 2}/30 = 1/6$
The cistern will be filled in 6 hours.
Question : 4 [SSC CGL TierI 2014]
A cistern is provided with two pipes A and B. A can fill it in 20 minutes and B can empty it in 30 minutes. If A and B be kept open alternately for one minute each, how soon will the cistern be filled ?
a) 120 minutes
b) 121 minutes
c) 110 minutes
d) 115 minutes
Answer »Answer: (d)
Using Rule 7,
Part of the tank filled in first two minutes
= $1/20  1/30 = {3  2}/60 = 1/60$
Part of tank filled in 114 minutes
= $57/60 = 19/20$
Remaining part of cistern will be filled in 115th minute
Question : 5 [SSC CGL Prelim 2002]
A cistern can be filled with water by a pipe in 5 hours and it can be emptied by a second pipe in 4 hours. If both the pipes are opened when the cistern is full, the time in which it will be emptied is :
a) 20$1/2$ hours
b) 9 hours
c) 18 hours
d) 20 hours
Answer »Answer: (d)
According to the question
Cistern filled in 1 hour = $1/5$ part
Cistern emptied in 1 hour = $1/4$ part
When the both pipes are opened, simultaneously ;
Cistern emptied in 1 hour
= $1/4  1/5 = {5  4}/20 = 1/20$ part
The time in which it will be emptied = 20 hours.
Using Rule 7,
A tap 'A' can fill a tank in 'x' hours and 'B' can empty the tank in 'y' hours. Then (a) time taken to fill the tank
when both are opened = $({xy}/{x  y})$ : x > y
b) time taken to empty the tank
when both are opened = $({xy}/{y x})$ : y > x
Here, x = 5, y = 4
Required time = $({xy}/{x  y})$ hrs
= ${5 × 4}/{5  4}$ hrs = 20 hrs.
IMPORTANT QUANTITATIVE APTITUDE EXERCISES
Model 1 Basic Pipes & Cisterns Problems Shortcuts »
Click to Read...Model 1 Basic Pipes & Cisterns Problems Online Quiz
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QUANTITATIVE APTITUDE CATEGORIES

» Number System

» Average

» LCM & HCF

» Percentage

» Profit & Loss

» Time & Work

» Pipes & Cisterns

» Time & Distance

» Trains

» Compound Interest

» Simplification

» Discount

» Power

» Permutations & Combination

» Ratio & Proportion

» Advance Math

» Algebraic Expressions

» Trigonometric Ratios & Identities

» Simple Interest

» Alligation & Mixtures

» Boats & Streams

» Set Theory

» Linear Equations

» Quadratic Equations

» Mensuration

» Squareroots & Cuberoots

» Data Sufficiency

» Logarithm

» Probability

» Statistics
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