# model 1 profit x after discount y Practice Questions Answers Test with Solutions & More Shortcuts

#### discount PRACTICE TEST [4 - EXERCISES]

model 1 profit x after discount y

model 2 hiking & discounting

model 3 successive discount

model 4 mixed discount problems of marked price

**Question : 1**

A shopkeeper marks his goods 20% above his cost price and gives 15% discount on the marked price. His gain percent is

a) 1%

b) 2%

c) 5%

d) 4%

Answer »Answer: (b)

If the C.P. of goods be Rs.100, then

Marked price = Rs.120

S.P. = ${120 × 85}/100$ = Rs.102

Hence, Profit per cent = 2%

**Using Rule 8,**

A tradesman marks his goods r% above his cost price. If he allows his customers a discount of $r_1$% on the marked price. Then is profit or loss per cent is

${r × (100 - r_1)}/100 - r_1$

(Positive sign signifies profit and negative sign signifies loss).

Here, r = 20%, r1 = 15%

Gain % = ${r × (100 - r_1)}/100 - r_1$

= ${20 × (100 - 15)}/100 - 15$

= ${20 × 85}/100 - 15$

= 17 - 15 = 2%

**Question : 2**
[SSC DEO 2009]

The marked price of a radio is Rs.4,800. The shopkeeper allows a discount of 10% and gains 8%. If no discount is allowed, his gain per cent will be

a) 25%

b) 22%

c) 18%

d) 20%

Answer »Answer: (d)

Let CP of radio be Rs.x.

According to the question,

${108x}/100 = 4800 × 90/100 = 4320$

$x {4320 × 100}/108$ = Rs.4000

If no discount is allowed,

Gain per cent

= $800/4000 × 100 = 20%$

**Using Rule 6,**

M.P. = Rs.4800, D = 10%, r = 8%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$4800/\text"CP" = {100 + 8}/{100 - 10}$

C.P. = ${4800 × 90}/108$

C.P. = 4000

Gain % (without discount)

= ${4800 - 4000}/4000 × 100$

= $800/4000 × 100$ = 20%

**Question : 3**
[SSC CPO S.I.2003]

The marked price of an electric iron is Rs.690. The shopkeeper allows a discount of 10% and gains 8%. If no discount is allowed, his gain per cent would be

a) 28%

b) 25%

c) 20%

d) 24%

Answer »Answer: (c)

Marked price = Rs.690

Discount = 10%

SP = ${690 × 90}/100$ = Rs.621

Profit = 8%

CP = $621/108 × 100$ = Rs.575

Profit without discount

= 690 - 575 = Rs.115

Profit per cent

= $115/575 × 100$ = 20%

**Using Rule 9,**

The marked price of an article is fixed in such a way that after allowing a discount of r% a profit of R% is obtained. Then the marked price of the article is $({r + R}/{100 - r} × 100)$% more than its cost price.

Here, r = 10% R = 20%

Required percentage

= ${r + R}/{100 - r} × 100$%

= ${10 + 20}/{100 - 10} × 100$%

= $30/90 × 100% = 33{1}/3%$

Gain % = $\text"S.P. - C.P."/\text"C.P." × 100$

(without discount)

= ${480 - 400}/400 × 100$

= $80/400 × 100$ = 20%

**Using Rule 6,**

If r% of profit or loss occur after giving D% discount on marked price, then

$\text"MP"/\text"CP" = {100 ± r}/{100 - D}$

(positive sign for profit and negative for loss)

Here, M.P. = Rs.690, D = 10%, r = 8%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$600/\text"CP" = {100 + 8}/{100 - 10}$

C.P. = ${690 × 90}/108$

C.P. = Rs.575

Gain % (without discount)

= ${690 - 575}/575 = 100%$

= $115/575 × 100%$ = 20%

**Question : 4**
[SSC CGL Tier-I 2013]

How much percent more than the cost price should a shopkeeper mark his goods so that after allowing a discount of 25% on the marked price, he gains 20% ?

a) 55%

b) 60%

c) 70%

d) 50%

Answer »Answer: (b)

Let C.P.of article = Rs.100

If the marked price of article be x, then

$x × 75/100$ = 120

$x = {120 × 100}/75$ = 160

i.e. 60% above the cost price

**Using Rule 9,**

r = 25%, R = 20%

Required percentage

= $({r + R}/{100 - r} × 100)$%

= $({25 + 20}/{100 - 25} × 100)$%

= $45/75 × 100$ = 60%

**Question : 5**

An article of cost price Rs.8,000 is marked at Rs.11,200. After allowing a discount of x% a profit of 12% is made. The value of x is

a) 23%

b) 22%

c) 21%

d) 20%

Answer »Answer: (d)

S.P. for a profit of 12%

= ${8000 × 112}/100$ = Rs.8960

Discount = 11200 - 8960 = Rs.2240

If the discount per cent be x, then

${11200 × x}/100 = 2240$

$x = {2240 × 100}/11200 = 20%$

**Using Rule 6,**

Here, M.P. = Rs.11200, C.P. = Rs.8000

r =12% D = x%

$\text"MP"/\text"CP" = {100 + r}/{100 - D}$

$11200/8000 = {100 + 12}/{100 - x}$

= $11200/8000 = 112/{100 - x}$

100 - x = 80 ⇒ x = 20%

###### IMPORTANT quantitative aptitude EXERCISES

###### discount Shortcuts and Techniques with Examples

###### quantitative aptitude CATEGORIES

## Recent Blog Posts

## Recently Added Subject & Categories For All Competitive Exams

#### Important General Science Biology Practice MCQ Questions

Top General Science Biology In Human Welfare Based Multiple Choice Questions And Answers, Practice MCQ Test For All Competitive Exams, NEET, SSC, Interview

Continue Reading »

#### Top 199+ General Science Biology Practice Test, MCQ PDF

Most Important General Science Biology Human Welfare Multiple Choice Questions And Answers (MCQ) PDF, Practice Test For All Competitive Exams, SSC, NEET, RRB

Continue Reading »

#### New General Science Biology MCQ Online Practice Test, PDF

Top Most General Science Biology Food Production Multiple Choice Questions And Answers (MCQ), Online GK Practice Test, PDF For All Competitive Exams, NEET

Continue Reading »

#### 150+ Frequently Asked Biology MCQs for Competitive Exams

Biology Frequently Asked Multiple Choice Questions And Answers (MCQ) For All Competitive Exams. General Science GK Practice Test, PDF For BANK, SSC, RAILWAY

Continue Reading »