time and work Model Questions & Answers, Practice Test for ssc steno grade c d 2024

Answer: (a)

According to the formula,

${M_1D_1}/{W_1} = {M_2D_2}/{W_2}$

Here, $M_1 = 15, D_1 = 16, W_1 = W_2$ = 1

$M_2 = 24 and D_2$ = ?

⇒${15 × 16}/1 = {24 × D_2}/1$

$D_2 = {15 × 16}/{24}$ = 10

10 days are required to complete the work.

Answer: (a)

The two filler tap can fill the $(1/20 + 1/30) or 1/{12}$ part of tank in 1 min.

∴ The two filler tap can fill the tank in 12 min.

∴ Half of the tank will be filled in 6 min.

Hence, it took (24 – 6 = 18 min.) to fill the remaining half of the tank when the outlet pump is opened. Thus, the total time required to empty half of the tank

= ${18 × 6}/{18 - 6} = {18 × 6}/{12}$ = 9 minutes

Thus, capacity of the tank = 100 × 9 × 2 = 1800 litres

Answer: (a)

Time required = (2 hrs 30 min – 50 min) = 1hr 40 min

= 1$2/3$ hrs

∴ Required speed = (50 × $3/5$) km/hr = 30 km/hr.

Original speed = (50 × $2/5$) km/hr = 20 km/hr.

∴ Difference in speed = (30 – 20) km/hr = 10 km/hr.

Answer: (d)

Let the remaining food last for x days.

1000 soldiers had provisions for (30 – 10) = 20 days

(1000 + 1000) men had provisions for x days.

More men, less days (indirect proportion)

∴ 2000 : 1000 : : 20 : x

⇒${2000}/{1000} = {20}/x$

x = 10 days

Answer: (a)

Average speed = ${\text"Total distance"}/{\text"Total time"}$

= ${400 × 4 × 9}/{88 + 96 + 89 + 87} = {400 × 4 × 9}/{360}$

= 40 metres/minutes