Practice Marks and examinations - quantitative aptitude Online Quiz (set-1) For All Competitive Exams

Q-1)   In the annual examination Mahuya got 10% less marks than Supriyo in Mathematics. Mahuya got 81 marks. The marks of Supriyo are

(a)

(b)

(c)

(d)

Explanation:

Let marks obtained by Supriyo = x

${9x}/10 = 81 ⇒ x = {81 × 10}/9 = 90$


Q-2)   In a group of students, 70% can speak English and 65% can speak Hindi. If 27% of the students can speak none of the the two languages, then what per cent of the group can speak both the languages ?

(a)

(b)

(c)

(d)

Explanation:

Let total number of students = 100

27 students speak none of the two languages.

It means only 73 students speak either Hindi or English or both.

Let x students speak both languages.

∴ 73 = 70 – x + x + 65 – x

x = 70 + 65 – 73 = 62%


Q-3)   A student has to obtain 33% of total marks to pass. He got 25% of total marks and failed by 40 marks. The number of total marks is

(a)

(b)

(c)

(d)

Explanation:

Let the total marks be x.

According to the question,

25% of x + 40 = 33% of x

(33 – 25)% of x = 40

8% of x = 40

x = ${40 × 100}/8$ = 500


Q-4)   72% of the students of a certain class took Biology and 44% took Mathematics. If each student took at least one subject from Biology or Mathematics and 40 took both, then the total number of students in the class is :

(a)

(b)

(c)

(d)

Explanation:

Let the number of students in the class be 100.

Number of students in Biology = 72 and number of students in Maths = 44.

Number of students opting for both subjects = 72 + 44 – 100 = 16

Since, When 16 students opt for both subjects, total number of students = 100

When 40 students opt for both subjects,

total number of students = $100/16 × 40$ = 250


Q-5)   A student scored 32% marks in science subjects out of 300. How much should he score in language papers out of 200 if he is to get overall 46% marks ?

(a)

(b)

(c)

(d)

Explanation:

46% of 500 = ${500 × 46}/100 = 230$

32% of 300 = ${300 × 32}/100 = 96$

Required marks = 230 – 96 = 134

Let x% of 200 = 134

${200 × x}/100 = 134$

2x = 134 ⇒ x = $134/2$ = 67%


Q-6)   In an examination 80% of the boys passed in English and 85% passed in Mathematics, while 75% passed in both. If 45 boys failed in both, the number of boys who sat for the examination was

(a)

(b)

(c)

(d)

Explanation:

Successful boys in English or Maths or both

= 80 + 85 – 75 = 90%

Unsuccessful boys = 10%

Total number of boys = $100/10 × 45$ = 450


Q-7)   In an examination 60% of the students pass in English, 70% pass in Hindi and 40% pass in both. What percent of students fail in both English and Hindi?

(a)

(b)

(c)

(d)

Explanation:

The percentage of students who pass in one or two or both subjects

= 60 + 70 – 40 = 90

Percentage of failed students = 100 – 90 = 10%


Q-8)   In an examination, 65% of the students passed in Mathematics, 48% passed in Physics and 30% passed in both. How much per cent of students failed in both the subjects ?

(a)

(b)

(c)

(d)

Explanation:

n(M) = 65, n(P) = 48, n(M?P) = 30

n(M?P)= n(M) + n(P) – n(M?P)

= 65 + 48 – 30 = 83

Percent of students passed = 83

Percent of students failed= 17

Method 2 :

Students passed only in Math = 65 – 30 = 35%

Students passed only in Physics = 48 – 30 = 18%

Total passing % = 35 + 18 + 30 = 83%

Failed = 100 – 83 = 17%


Q-9)   25% of the candidates who appeared in an examination failed to qualify and only 450 candidates qualified. The number of candidates, who appeared in the examination, was

(a)

(b)

(c)

(d)

Explanation:

Clearly, 75 candidates qualify

75% of appearing candidates = 450

Number of appearing candidates

= ${450 × 100}/75 = 600$


Q-10)   In a class 60% of the student pass in Hindi and 45% pass in Sanskrit. If 25% of them pass in atleast one subject, what percentage of the students fail in both the subjects ?

(a)

(b)

(c)

(d)

Explanation:

25% of students pass in at least one subject i.e.; they pass in one or both subjects.

% of students who don't pass or fail in both subjects

= (100 – 25)% = 75%