find distance only section 3 Practice Questions Answers Test with Solutions & More Shortcuts

Question : 26 [SSC CGL Tier-I 2015]

Veena and Veeru both start from a point towards North. Veena turns to left after walking 10 km. Veeru turns to right after walking the same distance. Veena waits for some time and then walks another 5 km. Whereas Veeru walks only 3 km. They both then return towards South and walk 15 km. forward. How far is Veena from Veeru?

a) 15 km.

b) 10 km

c) 8 km.

d) 12 km.

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= (5 + 3) km = 8 km.

Question : 27

Raj travelled from a point X straight towards east to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point?

a) 20 metres

b) 70 metres

c) 10 metres

d) 50 metres

Answer: (c)

direction-and-distance

Question : 28 [SSC CGL Tier-1 2003]

Sandhya walks straight from point A to B which is 2 kms away. She turns left, at 90° and walks 8 kms to C, where she turns left again at 90° and walks 5 kms to D. At D she turns left at 90° and walks for 8 kms to E. How far is she from A to E ?

a) 3

b) 8

c) 2

d) 5

Answer: (a)

direction-and-distance-verbal-reasoning

The distance between A and E = 3km

Question : 29

A man walks 40 meters towards north. Then turning to his right, he walks 50 meter. Then turning to his left, he walks 30 meters. Again he turns to his left and walks 40 meters. How far is he from initial position?

a) $50√2$

b) $60√2$

c) $40√2$

d) $50√3$

e) None of these

Answer: (a)

Distance = $√(70^2 + 10^2) = √5000 = 50√2$

Question : 30

Rishu started walking towards East from a point 'X', walked 250 metres and reached the point 'P'. Again, he turned towards South, walked 50 metres and reached point Q. Again he turned towards east and walked 250 metres and reached point 'R. He again turned South, walked 50 metres and reached point S. What is the shortest distance between X and S?

a) 1100 metres

b) 590.9 metres

c) 509.9 metres

d) 561.2 metres

Answer: (c)

direction-and-distance

XS = $√{XT^2 + TS^2}$ = $√{500^2 + 100^2}$

$√{250000 + 10000}$ = 509.9 metres

IMPORTANT verbal reasoning EXERCISES

find distance only section 3 Online Quiz

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919 direction & distance sense test based verbal reasoning section 3 question answer with explanation pdf

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