type 1 angle between the hands of clock Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [Hotel Mgmt 012]

Find the angle between the hands of clock at 8 : 20.

a) 130°

b) 115°

c) 125°

d) 140°

Answer: (a)

∴ Angle traced by hour hand per minute =$(1/2)^o$

∴Angle traced by hour hand in 8h 20 min = ( 8 x 60 + 20) ×$ 1/2$ = 205°

Again, angle traced by minute hand per minute = 6°

∴ again traced by minute hand in 20 min = 20 × 6°

= 120° 

Therefore required angle = (250° - 120°) = 130°

Question : 2

What will be the angle between the hands of clock at 7 : 10?

a) 185°

b) 155°

c) 170°

d) 165°

Answer: (d)

∴ angle traced by hour hand per minute = $(1/2)^o$

∴ angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$

= $[{480 + 30} ×1/2]^o$ = 510 × $(1/2)^o$ = 255°

∴ Angle traced by minute hand per minute = 6°

∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°

∴ required angle = (255° - 180°) = 75°

Question : 3

Find the angle traced by hour hand of a correct clock between 8 O' clock and 2O' clock.

a) 180°

b) 168°

c) 150°

d) 144°

Answer: (a)

∴ Angle traced by hour hand per minute = $(1/2)^o$

∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°

Time period between 8 O' clock to 2 O' clock = 6h

∴ angle traced by hour hand in 6h = 30° × 6 = 180°

Question : 4 [M.A.T. 2010]

What angle will be traced by the hands of a clock at 7 : 35?

a) $7 1°/2$

b) $17 1°/2$

c) $27 1°/2$

d) $37 1°/2$

Answer: (b)

Angle traced by hour hand per minute = $(1/2)^o$

∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$

= (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$

∴ angle traced by minute hand per minute = 6°

Angle traced by minute hand in 35 min = 35 × 6° = 210°

∴ required angle = 227 1°/2 - 201° = 17$1°/2$

Question : 5 [S.S.C. (CPO) 2015]

What will be the angle between the hands of clock at 8 : 30?

a) 15°

b) 30°

c) 45°

d) 75°

Answer: (d)

∴ Angle traced by hour hand per minute = $(1/2)^o$

∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$

= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$

Then,  Angle traced by minute hand per minute = 6°

∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°

Hence, Required angle = (255° - 180°) = 75°

IMPORTANT verbal reasoning EXERCISES

Recently Added Subject & Categories For All Competitive Exams

Top 149+ Biology General Knowledge Practice MCQ Test

Top Biology Ecology & Environment Awareness General Knowledge Multiple Choice Questions And Answers. General Science GK Practice Test For Competitive Exams

December-16-2022 by Careericons

Continue Reading »

Important General Science Biology Practice MCQ Questions

Top General Science Biology In Human Welfare Based Multiple Choice Questions And Answers, Practice MCQ Test For All Competitive Exams, NEET, SSC, Interview

December-06-2022 by Careericons

Continue Reading »

Top 199+ General Science Biology Practice Test, MCQ PDF

Most Important General Science Biology Human Welfare Multiple Choice Questions And Answers (MCQ) PDF, Practice Test For All Competitive Exams, SSC, NEET, RRB

December-01-2022 by Careericons

Continue Reading »

New General Science Biology MCQ Online Practice Test, PDF

Top Most General Science Biology Food Production Multiple Choice Questions And Answers (MCQ), Online GK Practice Test, PDF For All Competitive Exams, NEET

November-29-2022 by Careericons

Continue Reading »