type 1 angle between the hands of clock Practice Questions Answers Test with Solutions & More Shortcuts
clocks PRACTICE TEST [5 - EXERCISES]
type 1 angle between the hands of clock
type 2 position of hands of the clock
type 3 faulty clock
type 4 time gained or lost by clock
type 5 comparing clocks
Question : 1 [Hotel Mgmt 012]
Find the angle between the hands of clock at 8 : 20.
a) 130°
b) 115°
c) 125°
d) 140°
Answer »Answer: (a)
∴ Angle traced by hour hand per minute =$(1/2)^o$
∴Angle traced by hour hand in 8h 20 min = ( 8 x 60 + 20) ×$ 1/2$ = 205°
Again, angle traced by minute hand per minute = 6°
∴ again traced by minute hand in 20 min = 20 × 6°
= 120°
Therefore required angle = (250° - 120°) = 130°
Question : 2
What will be the angle between the hands of clock at 7 : 10?
a) 185°
b) 155°
c) 170°
d) 165°
Answer »Answer: (d)
∴ angle traced by hour hand per minute = $(1/2)^o$
∴ angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]^o$ = 510 × $(1/2)^o$ = 255°
∴ Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (255° - 180°) = 75°
Question : 3
Find the angle traced by hour hand of a correct clock between 8 O' clock and 2O' clock.
a) 180°
b) 168°
c) 150°
d) 144°
Answer »Answer: (a)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°
Time period between 8 O' clock to 2 O' clock = 6h
∴ angle traced by hour hand in 6h = 30° × 6 = 180°
Question : 4 [M.A.T. 2010]
What angle will be traced by the hands of a clock at 7 : 35?
a) $7 1°/2$
b) $17 1°/2$
c) $27 1°/2$
d) $37 1°/2$
Answer »Answer: (b)
Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$
= (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$
∴ angle traced by minute hand per minute = 6°
Angle traced by minute hand in 35 min = 35 × 6° = 210°
∴ required angle = 227 1°/2 - 201° = 17$1°/2$
Question : 5 [S.S.C. (CPO) 2015]
What will be the angle between the hands of clock at 8 : 30?
a) 15°
b) 30°
c) 45°
d) 75°
Answer »Answer: (d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$
Then, Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
Hence, Required angle = (255° - 180°) = 75°
IMPORTANT verbal reasoning EXERCISES
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