# type 1 angle between the hands of clock Practice Questions Answers Test with Solutions & More Shortcuts

#### clocks PRACTICE TEST [5 - EXERCISES]

Question : 1 [Hotel Mgmt 012]

Find the angle between the hands of clock at 8 : 20.

a) 130°

b) 115°

c) 125°

d) 140°

∴ Angle traced by hour hand per minute =\$(1/2)^o\$

∴Angle traced by hour hand in 8h 20 min = ( 8 x 60 + 20) ×\$ 1/2\$ = 205°

Again, angle traced by minute hand per minute = 6°

∴ again traced by minute hand in 20 min = 20 × 6°

= 120°

Therefore required angle = (250° - 120°) = 130°

Question : 2

What will be the angle between the hands of clock at 7 : 10?

a) 185°

b) 155°

c) 170°

d) 165°

∴ angle traced by hour hand per minute = \$(1/2)^o\$

∴ angled traced by hour hand in 8 h 30 min =\$[{(8 × 60) + 30}x1/2]^o\$

= \$[{480 + 30} ×1/2]^o\$ = 510 × \$(1/2)^o\$ = 255°

∴ Angle traced by minute hand per minute = 6°

∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°

∴ required angle = (255° - 180°) = 75°

Question : 3

Find the angle traced by hour hand of a correct clock between 8 O' clock and 2O' clock.

a) 180°

b) 168°

c) 150°

d) 144°

∴ Angle traced by hour hand per minute = \$(1/2)^o\$

∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°

Time period between 8 O' clock to 2 O' clock = 6h

∴ angle traced by hour hand in 6h = 30° × 6 = 180° Question : 4 [M.A.T. 2010]

What angle will be traced by the hands of a clock at 7 : 35?

a) \$7 1°/2\$

b) \$17 1°/2\$

c) \$27 1°/2\$

d) \$37 1°/2\$

Angle traced by hour hand per minute = \$(1/2)^o\$

∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × \$1°/2\$

= (420 + 35) × 1°/2 = 455 × \$1°/2\$ = 227 \$1°/2\$

∴ angle traced by minute hand per minute = 6°

Angle traced by minute hand in 35 min = 35 × 6° = 210°

∴ required angle = 227 1°/2 - 201° = 17\$1°/2\$ Question : 5 [S.S.C. (CPO) 2015]

What will be the angle between the hands of clock at 8 : 30?

a) 15°

b) 30°

c) 45°

d) 75°

∴ Angle traced by hour hand per minute = \$(1/2)^o\$

∴ Angled traced by hour hand in 8 h 30 min =\$[{(8 × 60) + 30}x1/2]^o\$

= \$[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°\$

Then,  Angle traced by minute hand per minute = 6°

∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°

Hence, Required angle = (255° - 180°) = 75°

#### type 1 angle between the hands of clock Online Quiz

###### RECENT BLOGS    ## Recently Added Subject & Categories For All Competitive Exams

#### Coded Inequalities Reasoning Questions & Answers For Bank

New 150+ Coded Inequalities Verbal Reasoning Multiple-Choice Questions and Answers Free Practice Test & Online Quiz PDF For All IBPS PO SO & CLERK 2024 Exams

28-Nov-2023 by Careericons

#### 150+ Problem Solving Questions and Answers For Bank Exams

Problem-Solving Verbal Reasoning Concepts based Multiple Choice Questions and Answers Mock Test & Online MCQ Quiz for All 2024 Upcoming IBPS PO Clerk SO Exam

28-Nov-2023 by Careericons

#### New 150+ Syllogism Verbal MCQ Test PDF For IBPS RRB Exams

Free Syllogism Practice Multiple Choice Questions with Solved Answer PDF and All Verbal Reasoning Topics Online Mock Test For IBPS RRB PO & Clerk Exams 2024.

27-Nov-2023 by Careericons

#### New 200+ Syllogism Questions & Answers PDF For SSC Exams

Free Verbal Reasoning Syllogism Multiple Choice Questions with Solved Answer PDF & Online Mock Test. Prepare for all upcoming SSC CGL, CHSL, MTS Exams 2024

25-Nov-2023 by Careericons