find distance only section 6 Practice Questions Answers Test with Solutions & More Shortcuts

direction & distance sense test PRACTICE TEST [15 - EXERCISES]

find directions only

find distance only

find both direction & distance

find directions only section 2

find directions only section 3

find directions only section 4

find directions only section 5

find directions only section 6

find distance only section 2

find distance only section 3

find distance only section 4

find distance only section 5

find distance only section 6

find both direction & distance section 2

find both direction & distance section 3
DIRECTIONS:
  1. Point B is 9 km east of point A.
  2. Point T is 6 km south of point B.
  3. Point S is 4 km west of point T.
  4. Point T is 8 km west of point G.

Question : 1

A person starts from point S, walks 3 km towards south and reaches point D. Next he takes two right turns and reaches point A. How much distance has he travelled?

a) 20 km

b) 17 km

c) 18 km

d) 14 km

e) 11 km

Shortcut »

Answer: (c)

Let after first right turn he is at point K. Since after turn from K he reaches at point A so point K is in south of point A.

So he has travelled SD + DK + KA = 3 + (9-4) + (3+6) = 17 km

Question : 2

A person is standing on midpoint of line TG. Find his shortest distance from point B?

a) $5√14 km$

b) $6√3 km$

c) $3√15 km$

d) $2√13 km$

e) None of these

Shortcut »

Answer: (d)

Let that point be Y. So Midpoint of TG means TY = $8/2$ = 4 km

So BY = $√(BT^2 + TY^2 ) = √ (6^2 + 4^2 ) = 2√13 km$

DIRECTIONS:
  1. Point A is 8 m west of point B.
  2. Point E is 2 m east of point F.
  3. Point G is 3 m east of point H.
  4. Point E is 3 m north of point of point D.
  5. Point C is 9 m west of point D.
  6. Point G is 9 m north of point F.
  7. Point C is 6 m south of point B.

Question : 3

Find distance AH.

a) $7√5 m$

b) $6√6 m$

c) $7√6 m$

d) $6√5 m$

e) None of these

Shortcut »

Answer: (d)

Vertical distance = GF – (CB – ED) = 9 – (6-3) = 6

Horizontal distance = AB + (CD – (HG + FE)) = 8 + (9 – (3+2) = 12

Required distance AH = $√ (6^2 + 12^2 ) = 6√5 m$

Question : 4

A person starts from point G in east direction. Walks for 6 m, takes a right turn, now walks for 5 m. Now he takes a left turn, walks for 3 m, then after two consecutive right turns he reaches point E. Find the distance travelled by him to reach point E.

a) 25 m

b) 23 m

c) 27 m

d) 24 m

e) 28 m

Shortcut »

Answer: (a)

6 + 5+ 3 + (9-5) + (3+4) = 25 m

Question : 5 [SSC Level DEO & LDC 2012]

A cyclist goes 30 km to North and then turning to East he goes 40 km. Again he turns to his right and goes 20 km. After this he turns to his right and goes 40 km. How far is he from his starting point ?

a) 10 km

b) 40 km

c) 20 km

d) 25 km

Shortcut »

Answer: (a)

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