find distance only section 3 Practice Questions Answers Test with Solutions & More Shortcuts

Question : 16

A person starts from a point in east direction. He walks 6 km and turns to his left. Next he walks 4 km and turns to his left again. Next he walks 2 km and turns towards south direction. He stops after walking 8 km. Find his distance from the starting point.

a) $3√2 km$

b) $4√2 km$

c) 16 km

d) $4√4 km$

e) 8 km

Answer: (b)

Required distance = $√ (4^2 + 4^2 ) = 4√2 km$

Question : 17 [SSC CAPFs SI, CISF ASI 2015]

Arjun starts from school and walks 4 km towards West, turns right and walks 3 km. Then he planned to return back to school, but only in the shortest path. What is the shortest distance between the school and the point where he stopped ?

a) 16 km

b) 5 km

c) 3 km

d) 25 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

AC = $√{AB^2 + BC^2}$

= $√{4^2 + 3^2}$

= $√{16+ 9}$

= $√{25}$ 

= 5 km

Question : 18

Namita walks 14 metres towards west, then turns to her right and walks 14 metres and then turns to her left and walks 10 metres. Again turning to her left she walks 14 metres. What is the shortest distance (in metres) between her starting point and the present position?

a) 28

b) 10

c) 24

d) 38

e) None of these

Answer: (c)

direction-and-distance

Required answer: DA + SA = 10 + 14 = 24m.

Question : 19 [SSC (10+2) Level DEO & LDC 2011]

A, B, C, D and E are standing in a line facing North. E is standing 40 metres left to B. A is standing 20 metres left to C. D is standing 20 metres right to E and 50 metres right to C. What is the distance between A and B ?

a) 80 metres

b) 100 metres

c) 70 metres

d) 90 metres

Answer: (d)

direction-and-distance-verbal-reasoning

AB = (20 + 30 + 20 + 20) m

= 90 metres

Question : 20

A man walks 30 metres towards South. Then, turning to his right, he walks 30 metres. Then, turning to his left, he walks 20 metres. Again, he turns to his left and walks 30 metres. How far is he from his initial position ?

a) 60 metres

b) 30 metres

c) 20 metres

d) 80 metres

e) None of these

Answer: (e)

direction-and-distance-verbal-reasoning

The movements of the man are as shown in the figure,

∴ Man's distance from initial position A

= AE = (AB + BE) = (AB + CD)

= (30 + 20) = 50m.

IMPORTANT verbal reasoning EXERCISES

find distance only section 3 Online Quiz

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919 direction & distance sense test based verbal reasoning section 3 question answer with explanation pdf

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