find distance only section 3 Practice Questions Answers Test with Solutions & More Shortcuts
direction & distance sense test PRACTICE TEST [15 - EXERCISES]
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
Question : 1
Hari travelled 17 km to the east, he turned left and went 15 km, he again turned left and went 17 km. How far is he from the starting point ?
a) 2 km
b) 32 km
c) 17 km
d) 15 km
Answer »Answer: (d)
Question : 2
If point M is 4 km north of point G and point O is south if point G such that point G is mid way between points M and N. Find distance MN + AE.
a) 25 km
b) 19 km
c) 23 km
d) Cannot be determined
e) None of these
Answer »Answer: (c)
MN = 4+4 = 8 km
AE = $√(AD^2 + DE^2)$
= $√(12^2 + 9^2)$ = 15 km
so required ans = 8 + 15 = 23 km
Question : 3 [SSC Steno (Gr 'C' & 'D') 2011]
A travelled westward 8km, turned left and travelled 3 km, turned right and travelled 9 km. He then travelled north 3 km. How far is he from the starting point ?
a) 17 km
b) 11 km
c) 15 km
d) 19 km
Answer »Answer: (a)
Required distance
= 8 km + 9 km
= 17km
Question : 4 [SSC CHSL (10+2) DEO & LDC 2014]
Ram walks 2 km to the East, then he turns to South and walks 6 km. He again turns to East and walks 2 km. Then he turns to North and walks 12 km. How far is he from the starting point ?
a) 7.1 km
b) 7.3 km
c) 7 km
d) 7.2 km
Answer »Answer: (d)
Required distance
AE = $√{AF^2 + FE^2}$
= $√{4^2 + 6^2}$
= $√{16+ 36}$
= $√{52}$
= 7.2 km
Question : 5
A man leaves for his office from his house. He walks towards East. After moving a distance of 20 m, he turns South and walks 10 m. Then he walks 35m towards the West and further 5m towards the North. He then turns towards East and walks 15 m. What is the straight distance (in metres) between his initial and final position?
a) Cannot be determined
b) 0
c) 5
d) None of these
Answer »Answer: (c)
The movements of the man from A to F are as shown in Figure
Clearly, DC = AB + EF
F is in line with A
Also, AF = (BC – DE) = 5m.
So, the man is 5 metres away from his initial position.
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