# Arithmetical Reasoning Section 1 MCQ Practice Questions Answers Test With Solutions & More Shortcuts

#### ARITHMETICAL REASONING PRACTICE TEST [2 - EXERCISES]

Question : 1

The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner ?

a) 61

b) 15

c) 29

d) None of these

Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 – 1 = 29.

Question : 2

Jaideep was given some money by his mother on his birthday. Jaideep spent all of it in five stores. In each store he spent one rupee more than half of what he had when he came in. How much did he get from his mother?

a) Rs.46

b) Rs.25

c) Rs.30

d) Rs.52

Question : 3

Four children A, B, C and D are having some chocolates each. A gives B as many as he already has, he gives C twice of what C already has and he gives D thrice of what D already has. Now, D gives 1/8th of his own chocolates to B. Then A gives 10% chocolates he now owns to C and 20% to B. Finally, all of them have 35 chocolates each. What is the original number of chocolates each had in the beginning ?

a) A-70, B-25, C-25, D-20

b) A -110, B-10, C-10, D-10

c) A-90, B-20, C-20, D-10

d) A-125, B-5, C-5, D-5

Work with options we find that option (b) is correct.

 Option (b) A B C D Beginning 110 10 10 10 A gave 110 - 60 = 50 10 + 10 = 20 10 + 20 = 30 10 + 30 = 40 D gave 20 + 5 = 25 40 - 5 = 35 A gave 50 - 15 = 35 25 + 10 = 35 30 + 5 = 35

Question : 4

Four persons, Alok, Bhupesh, Chander and Dinesh have a total of ` 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact ` 5 more than Dinesh has. Who has the maximum amount of money ?

a) Chander

b) Alok

c) Bhupesh

d) Dinesh

a + b + c + d = 100

Also, a + b = c + d = 50

c = \$d/2, ∴ d/2 + d\$ = 50 ⇒ d = 33.3

∴ d > c

Also, a > b & between a and d, a = d + 5

∴ a > d

∴ Alok (b) has the maximum money.

Question : 5

A group of 1200 persons consisting of captains and soldiers is travelling in a train. For every 15 soldiers there is one captain. The number of captains in the group is ?

a) 80

b) 70

c) 75

d) 85

Generally we may commit mistake of dividing 1200/15. But out of 16 persons there is one captain. so, it will be 1200/16 = 75

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