type 1 angle between the hands of clock Detailed Explanation And More Example
MOST IMPORTANT verbal reasoning - 5 EXERCISES
The following question based on clocks topic of verbal reasoning
(a) 15°
(b) 30°
(c) 45°
(d) 75°
The correct answers to the above question in:
Answer: (d)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]° = 510 × (1/2)^o = 255°$
Then, Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
Hence, Required angle = (255° - 180°) = 75°
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Read more find angle between hands clock Based Verbal Reasoning Questions and Answers
Question : 1
At what angle the hands of a clock are inclined at 15 minutes past 5?
a) $\text"58"1°/2$
b) 64°
c) $\text"67"1°/2$
d) $\text"72"1°/2$
Answer »Answer: (c)
Angle traced by hour hand in 21/4 hrs =$ (360/12 × 21/4)^o = 157 1°/2$
Angle traced by min. Hand in 15 min = $(360/12 × 15)^o = 90°$
∴ Required angle = $(157 1°/2) - 90° = 67 1°/2$.
Question : 2
A clock gains 5 minutes in one hour. Therefore, the angle traversed by the minute hand in 1 hour is
a) 360°
b) 390°
c) 390.5°
d) None of these
Answer »Answer: (b)
Clearly, the minute hand traverses 65 minutes in 1 hour.
∴ Required angle = $(360/60 × 65)^o = 360°$
Question : 3
Match List I with List II and select the correct answer using the codes given below the lists:
List I (Time) | List II (Angle between hour hand and minute hand of a clock) |
A. 1:10 PM | 20° |
B. 2:15 PM | 22$1/2$° |
C. 8:40 PM | 24° |
25° | |
30° |
a) A-4, B-2, C-1
b) A-4, B-3, C-2
c) A-5, B-2, C-1
d) A-4, B-3, C-2
Answer »Answer: (a)
(A) Angle traced by hour hand in$ 7/6 hrs = (360/12 × 7/6)^o = 35°$
Angle traced by minute hand in $10 min = (360/60 × 10)^o = 60°$
∴ Required angle = (60° - 35°) = 25°
(B) Angle traced by hour hand in $9/4 hrs = (360/12 × 9/4)^o = 67 1°/2$
Angle traced by minute hand in $15 min = (360/60 × 15)^o = 90°$
∴ Required angle = $(90° - 67 1°/2) = 22 1°/2$
(C) Angle traced by hour hand in $26/3 hrs = (360/12 × 26/3)^o = 260°$
Angle traced by minute hand in $40 min = (360/60 × 40)^o$ = 240°
∴ Required angle = (260° - 240°) = 20°
Question : 4
What angle will be traced by the hands of a clock at 7 : 35?
a) $7 1°/2$
b) $17 1°/2$
c) $27 1°/2$
d) $37 1°/2$
Answer »Answer: (b)
Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 7 h 35 min = [(7 × 60) + 35] × $1°/2$
= (420 + 35) × 1°/2 = 455 × $1°/2$ = 227 $1°/2$
∴ angle traced by minute hand per minute = 6°
Angle traced by minute hand in 35 min = 35 × 6° = 210°
∴ required angle = 227 1°/2 - 201° = 17$1°/2$
Question : 5
Find the angle traced by hour hand of a correct clock between 8 O' clock and 2O' clock.
a) 180°
b) 168°
c) 150°
d) 144°
Answer »Answer: (a)
∴ Angle traced by hour hand per minute = $(1/2)^o$
∴ Angle traced by hour hand in 1 h = 1°/2 × 60 = 30°
Time period between 8 O' clock to 2 O' clock = 6h
∴ angle traced by hour hand in 6h = 30° × 6 = 180°
Question : 6
What will be the angle between the hands of clock at 7 : 10?
a) 185°
b) 155°
c) 170°
d) 165°
Answer »Answer: (d)
∴ angle traced by hour hand per minute = $(1/2)^o$
∴ angled traced by hour hand in 8 h 30 min =$[{(8 × 60) + 30}x1/2]^o$
= $[{480 + 30} ×1/2]^o$ = 510 × $(1/2)^o$ = 255°
∴ Angle traced by minute hand per minute = 6°
∴ Angle traced by minute hand in 30 min = 30 × 6° = 180°
∴ required angle = (255° - 180°) = 75°
GET clocks PRACTICE TEST EXERCISES
type 1 angle between the hands of clock
type 2 position of hands of the clock
type 3 faulty clock
type 4 time gained or lost by clock
type 5 comparing clocks
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