type 2 position of hands of the clock Short Notes, Methods, Tips, Tricks & Techniques to Solve Problems
Type 2: "Finding The Hands Positions Of The Clock"
Clocks - Verbal Reasoning Problems With Basic Formulas, Shortcuts & Techniques PDF.
Posted By Careericons Team
In this type of question, there are certain conditions are given and the candidate has to find the time (i.e., the position of the hands of the clock). To solve these type of questions, you should have a basic knowledge of the positions & directions shown by the different hands in a clock.
Also see other types of clocks verbal resoning MCQ in detail,
- Type 1: Finding Angle Between the Hands of Clock,
- Type 3: Solving a Faulty Clock/ Correcting Clock,
- Type 4: Finding the Time Gained or Lost by a Clock, &
- Type 5: Comparing Different Timings of Clocks.
"CLOCKS" - VERBAL REASONING
- Meaning & Definition, Notes, Formulas, Methods, Techniques and Shortcuts to solve any problems on Clocks for any Competitive Examinations.
- What is a Clocks?
- What kind of measurements are taken using a Clocks?
- What are the Basic Conceptual Facts, Features & Functions of a Clocks in Verbal Reasoning?
- Top 10 Important Key Facts to Know about the Clocks in Verbal Reasoning:
- What are the different types of verbal reasoning questions/ problems based on Clocks that are asked in various competitive examinations?
Check our page & You will get the above followings in detail ⇒
Here are these type 2 clock related problems to find the position of the hands of the clock, you need to learn some techniques, formulas and shortcuts in solving these types of clock problems. Let us discuss one by one in order,
Top 7 Important Key Facts Used in Determining the Position of the Hands of a Clock - Verbal Reasoning
To solve these questions, follow the "7 important facts helps to find the positions hour hand and minute hand of a clock in a particular time", And which you should always keep in mind while solving such type of problems.
1. In every hour, both the hands are at right angles two times. In the case,
- Angle between the two hands = 90 °
- The two hands are 30 min spaces apart
2. In every hour, the two hands are in the same straight line two times.
- When both hands are coincident.
- Angle between the two hands = 0 °
- Minute spaces between the two hands = 0
- Both hands are in the same direction.
- When both hands are opposite to each other.
- Angle between the two hands = 180 °
3. In every 12 h, both hands coincide 11 time, (Between 11 and 1 O'Clock there is a common position at 12 O'clock).
∴ In 24 h, both hands coincides $\text"11 x 24"/{12}$ times = 22 times.
4. In every 12 h, both hands are in opposite direction 11 time, (Between 5 and 7 O'Clock there is a common position at 6 O'clock).
∴ In 24 h, both hands are in opposite direction $\text"11 x 24"/{12}$ times = 22 times.
5. In every 12 h, the two hands are in the same straight line 22 time,
∴ In 24 h, both hands are in opposite direction $\text"22 x 24"/{12}$ times = 44 times.
6. In every 12 h, the two hands are at right angles 22 time, (Between 2 and 4 O'Clock there is a common position at 3 O'clock and also between 8 and 10 O'Clock there is a common position at 9 O'clock ).
∴ In 24 h, both hands are at right angles $\text"22 x 24"/{12}$ times = 44 times.
7. If both the hands of a clock start moving together from the same position, then both the hands will coincide after every $65{5}/{11}$ min.
Important Shortcuts & Formulas For Verbal Reasoning MCQs Solve Problems With Finding Position of Hands of Clocks
The following formulas, shortcuts & tricks will be very useful to you in solving problems related in finding the different positions of the hour hand & the minute hand of a clock. These two hands has lots of common patterns as we seen earlier in the above box.
Here these formulas are classified in many ways with reaspect to its positions. It will be surely useful to you in lots of ways. Lets discuss indetail,
| Clocks Formulas & Explanations | |
|---|---|
To find time between x and (x + 1) O'clock, then time in a clock will be (5x ± t) ${12}/{11}$ mins past x. Where, t = Minute spacing between the minute and hour hand. i.e., Time between x and (x + 1) O'clock, the two hand will be t min apart at (5x ± t) ${12}/{11}$ mins past x. |
|
| If minute is ahead, then '+' sign is used and if hour hand is ahead, then '-' sign is used. | |
| Case-1 | For the hands to be coincident, put t = 0. i.e., at $\text"60 x"/{11}$ min past x, the hands of the clock coincide. |
| Case-2 | For the hands to be at right, put t = 15. i.e., at (5x ± 15) ${12}/{11}$ min past x, the hands of the clock will be at right angle. |
| Case-3 | For the hands to be in opposite directions, put t = 30. i.e., at (5x ± 30) ${12}/{11}$ min past x, the hands of the clock will be in opposite direction [use (+) sign, when x < 6 and (-) sign, when x > 6]. |
Some Example MCQ Questions & Answers with Explanation for Better Understanding of the Clocks Type -2 Concept
In this type of questions, some conditions are given from which you can find the correct time and using the time you have to find the positions of the clock which is the main objective of this type of questions. To find the positions of the hour hand and the minute hand at that particular time.
To solve these types of questions, an aspirant must have basic knowledge of the various characteristics common between the hands of a watch, the relevant techniques/ shortcuts and formulas used to find their positions.
Let's work out some examples based on finding the positions of the hands of a clock in a particular given time.
Example 1:At what time between 1 O'clock and 2 O'clock will the hands of the clock be together? |
|||
| (a) $4{5}/{11}$ min past 1 | (b) $5{5}/{11}$ min past 1 | ||
| (c) $3{4}/{11}$ min past 1 | (d) $6{5}/{11}$ min past 1 | ||
Hint: Answer: (b) Method 1: At 1 O'clock, hour hand is at 1 while minute hand is at 12. It means, the two hands are 5 min spaces apart. To be together, minute hand will have to gain 5 min over the hour hand. Since 55 min are gained in 60 min ∴ 5 min will be gained in ${60}/{55} x 5$ = ${60}/{11}$ min or $5{5}/{11}$ min Hence, the two hands will coincide at $5{5}/{11}$ min past 1. Method 2: In the given question, x = 1, (x+1) = 2 ∴ Required answer = ${60x}/{11}$ min past 1 = $\text"60 x 1"/{11}$ min past 1 = ${5}/{11}$ min past 1 |
|||
Example 2:At what time between 7 O'clock and 8 O'clock, will the hands of a clock be in the same straight line but not together? |
|
| (a) $5{5}/{11}$ min past 7 | (b) $5{4}/{11}$ min past 7 |
| (c) $6{5}/{11}$ min past 7 | (d) $3{4}/{11}$ min past 7 |
Hint: Answer: (a) Method 1: At 7 O'clock, minute hand is at 12 while hour hand is at 7 and both the hands are 25 min spaces apart. To be in the same straight line (but not together) both hands will have be 30 min spaces apart. ∴ Minute hand will have to gain (30 - 25) = 5 min spaces over hour hand. As we know, 55 min spaces are gained in 60 min. ∴ 5 min spaces will be gained in ${60}/{55} × 5$ min = ${60}/{11}$ min = $5{5}/{11}$ min Hence, the hands will be in the same straight line but not together at $5{5}/{11}$ min past 7. Method 2: In the given question, x = 7, (x + 1) = 8, x > 6 According to the formula, we know that Hands will be in the same straight line at (5x - 30) x ${12}/{11}$ min past x = (5 x 7 - 30) x ${12}/{11}$ min past 7 = (35 - 30) x ${12}/{11}$ min past 7 = 5 x ${12}/{11}$ min past 7 = 5 ${5}/{11}$ min past 7 |
|
Example 3:At what time between 3 O'clock and 4 O'clock will the hands of the clock be 4 min apart? |
| (a) $20{8}/{11}$ min past 3 and 12 min past 3 |
| (b) $20{8}/{11}$ min past 3 and 13 min past 3 |
| (c) $20{8}/{7}$ min past 3 and 12 min past 3 |
| (d) $20{8}/{9}$ min past 3 and 14 min past 3 |
Hint: Answer: (a) Method 1: At 3 O'clock, minute hand is 15 min spaces behind the hour hand. Case 1: When the minute hands is 4 min spaces behind the hour hand. In this case, minute hand has to gain (15 - 4) = 11 min spaces over hour hand ∵ 55 minute are gained in 60 min, ∴ 11 min are gained in $\text"60 × 11"/{55}$ min = 12 min Hence, the hands will be 4 min apart at 12 min past 3. Case 2: When the minute hand is 4 min spaces ahead of the hour hand. In this case, minute hand has to gain (15 + 4) = 19 min spaces over hour hand ∵ 55 min are gained in 60 min ∴ 19 min are gained in $({60}/{55} x 19)$ min = $(\text"12 x 19"/{11})$ min = $20{8}/{11}$ min Hence, the hands will be 4 min apart at 20 min past 3. Method 2: Given that, x = 3, (x + 1) = 4 and t = 4 Then, according to the formula, (5x ± t) = (5 x 3 ± 4) x ${12}/{11}$ min = (15 ± 4) x ${12}/{11}$ min Seperating '+' and '-' signs, we have (15 + 4) x ${12}/{11}$ min past 3 and (15 - 4) x ${12}/{11}$ min past 3 = $\text"19 x 12"/{11}$ min past 3 and $11 × {12}/{11}$ min past 3 = $20 {8}/{11}$ min past 3 and 12 min past 3 |
Different Types of Clocks - Verbal Reasoning MCQs with Practice Exercises Tests, Shortcuts PDF & Online Quiz Links
Several types of questions/ problems based on "Clocks" which are asked in various competitive examinations. Based on the diversity of questions ashed, we have classifiied them into following types in the table given below.
In this table you will get links to completely free practice test exercises complete with solved solutions, their shortcuts & tricks PDF and free online quiz.
Refer: Learn & Practice Verbal Classification Reasoning MCQ Tests with Example planations. Get Verbal Clocks Type 2: MCQ Exercises & Tests and Online Live Quiz.
clocks MCQ QUESTION & ANSWER EXERCISE
clocks Shortcuts and Techniques with Examples
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