Arithmetical Reasoning section 1 MCQ Practice Questions Answers Test with Solutions & More Shortcuts

Arithmetical Reasoning PRACTICE TEST [2 - EXERCISES]

Arithmetical Reasoning section 1 MCQ

Arithmetical Reasoning section 2 MCQ

Question : 6

A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what will he first touch a flag at 120 feet from the ground?

a) 6 p.m.

b) 4 p.m

c) 5 p.m.

d) 8 p.m.

Answer: (a)

Let ascent of the monkey in 1 hour = ( 30 – 20 ) = 10 feet.

So, the monkey ascends 90 feet in 9 hours i.e., 5 p.m.

Clearly, in the next 1 hour i.e., till 6 p.m.

The monkey ascends remaining 30 feet to touch the flag.

Question : 7

A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he holds?

a) 6

b) 4

c) 5

d) 7

Answer: (a)

Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.

Let the number of spades be x. Then, number of cubes = (7 – x).

Number of diamonds = 2 x number of spades = 2x

Number of hearts = 2 x number of diamonds = 4x

Total number of cards = x + 2x + 4x + 7 – x = 6x + 7.

Therefore 6x + 7 = 13 ⇔ 6x = 6 ⇔ x – 1.

Hence, number of clubs = (7 – x) = 6.

Question : 8

Mac has £ 3 more than Ken, but then Ken wins on the horses and trebles his money, so that he now has £ 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken's win ?

a) £ 13

b) £ 9

c) £ 11

d) £ 15

Answer: (a)

Let money with Ken = x. Then, money with Mac = x + £ 3.

Now, 3x = (x x + £ 3) + £ 2 ⇔ x = £ 5.

Therefore total money with Mac and Ken = 2x + £ 3 = £ 13.

Question : 9

Mr. X, a mathematician, defines a number as 'connected with 6 if it is divisible by 6 or if the sum of its digits is 6, or if 6 is one of the digits of the number. Other numbers are allenot connected with 6'. As per this definition, the number of integers from 1 to 60 (both inclusive) which are not connected with 6 is

a) 42

b) 18

c) 22

d) 43

Answer: (d)

Numbers from 1 to 60, which are divisible by 6 are : 6, 12, 18, 24, 30, 36, 42, 48, 54, 60.

There are 10 such numbers.

Numbers from 1 to 60, the sum of whose digits is 6 are 6, 15, 24, 33, 42, 51, 60.

There are 7 such numbers of which 4 are common to the above ones. So, there are 3 such uncommon numbers.

Numbers from 1 to 60, which have 6 as one of the digits are 6, 16, 26, 36, 46, 56, 60.

Clearly, there are 4 such uncommon numbers.

So, numbers 'not connected with 6'

= 60 – (10 + 3 + 4) = 43.

Question : 10

A girl counted in the following way on the fingers of her left hand : She started by calling the thumb 1, the index finger 2, middle finger 3, ring finger 4, little finger 5 and then reversed direction calling the ring finger 6, middle finger 7 and so on. She counted upto 1994. She ended counting on which finger?

a) Middle finger

b) Thumb

c) Index finger

d) Ring finger

Answer: (c)

Clearly, while counting, the numbers associated to the thumb will be : 1, 9,17, 25,.....

i.e. numbers of the form (8n + 1).

Since 1994 = 249 × 8 + 2, so 1993 shall correspond to the thumb and 1994 to the index finger.

IMPORTANT verbal reasoning EXERCISES

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