Practice Question and answers set 1 - verbal reasoning Online Quiz (set-1) For All Competitive Exams
Q-1) A player holds 13 cards of four suits, of which seven are black and six are red. There are twice as many diamonds as spades and twice as many hearts as diamonds. How many clubs does he holds?
(a)
(b)
(c)
(d)
Clearly, the black cards are either clubs or spades while the red cards are either diamonds or hearts.
Let the number of spades be x. Then, number of cubes = (7 – x).
Number of diamonds = 2 x number of spades = 2x
Number of hearts = 2 x number of diamonds = 4x
Total number of cards = x + 2x + 4x + 7 – x = 6x + 7.
Therefore 6x + 7 = 13 ⇔ 6x = 6 ⇔ x – 1.
Hence, number of clubs = (7 – x) = 6.
Q-2) The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner ?
(a)
(b)
(c)
(d)
Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 – 1 = 29.
Q-3) A group of 1200 persons consisting of captains and soldiers is travelling in a train. For every 15 soldiers there is one captain. The number of captains in the group is ?
(a)
(b)
(c)
(d)
Generally we may commit mistake of dividing 1200/15. But out of 16 persons there is one captain. so, it will be 1200/16 = 75
Q-4) Mr. X, a mathematician, defines a number as 'connected with 6 if it is divisible by 6 or if the sum of its digits is 6, or if 6 is one of the digits of the number. Other numbers are allenot connected with 6'. As per this definition, the number of integers from 1 to 60 (both inclusive) which are not connected with 6 is
(a)
(b)
(c)
(d)
Numbers from 1 to 60, which are divisible by 6 are : 6, 12, 18, 24, 30, 36, 42, 48, 54, 60.
There are 10 such numbers.
Numbers from 1 to 60, the sum of whose digits is 6 are 6, 15, 24, 33, 42, 51, 60.
There are 7 such numbers of which 4 are common to the above ones. So, there are 3 such uncommon numbers.
Numbers from 1 to 60, which have 6 as one of the digits are 6, 16, 26, 36, 46, 56, 60.
Clearly, there are 4 such uncommon numbers.
So, numbers 'not connected with 6'
= 60 – (10 + 3 + 4) = 43.
Q-5) There are four routes to travel from city A to city B and six routes from city B to city C. How many routes are possible to travel from the city A to city C ?
(a)
(b)
(c)
(d)
Total number of possible routes from the city A to city C = 4 × 6 = 24
Q-6) At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of daal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ?
(a)
(b)
(c)
(d)
Let the number of guests be x. Then number of bowls of rice = $x/2$; number of bowls of dal = $x/3$; number of bowls of meat = $x/4$.
∴ $x/2 + x/3 + x/4$ = 65
⇔ ${6x + 4x + 3x}/{12}$ = 65 ⇔ 13x = 65 × 12
⇔ x = $({65 × 12}/{13})$ = 60
Q-7) A man wears socks of two colours - black and brown. He has altogether 20 black socks and 20 brown socks in a drawer. Supposing he has to take out the socks in the dark, how many must he take out to be sure that he has a matching pair ?
(a)
(b)
(c)
(d)
Since there are socks of only two colours, so two out of any three socks must always be of the same colour.
Q-8) Jaideep was given some money by his mother on his birthday. Jaideep spent all of it in five stores. In each store he spent one rupee more than half of what he had when he came in. How much did he get from his mother?
(a)
(b)
(c)
(d)
Q-9) A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what will he first touch a flag at 120 feet from the ground?
(a)
(b)
(c)
(d)
Let ascent of the monkey in 1 hour = ( 30 – 20 ) = 10 feet.
So, the monkey ascends 90 feet in 9 hours i.e., 5 p.m.
Clearly, in the next 1 hour i.e., till 6 p.m.
The monkey ascends remaining 30 feet to touch the flag.
Q-10) Four persons, Alok, Bhupesh, Chander and Dinesh have a total of ` 100 among themselves. Alok and Bhupesh between them have as much money as Chander and Dinesh between them, but Alok has more money than Bhupesh; and Chander has only half the money that Dinesh has. Alok has in fact ` 5 more than Dinesh has. Who has the maximum amount of money ?
(a)
(b)
(c)
(d)
a + b + c + d = 100
Also, a + b = c + d = 50
c = $d/2, ∴ d/2 + d$ = 50 ⇒ d = 33.3
∴ d > c
Also, a > b & between a and d, a = d + 5
∴ a > d
∴ Alok (b) has the maximum money.