model 8 two article sold in different rates Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11 [SSC CHSL 2012]

A man sells two chairs at Rs.120 each and by doing so gains 25% on one chair and loses 25% on the other. His loss on the whole in Rs. is

a) 30

b) 25

c) 16

d) 20

Answer: (c)

C.P. of first chair = $100/125 × 120$ = Rs.96

C.P. of second chair = $100/75 × 120$ = Rs.160

∴ Loss = 160 + 96 - 240 = Rs.16

Question : 12 [SSC SO 2006]

The total cost price of two watches is Rs.840. One is sold at a profit of 16 per cent and the other at a loss of 12 per cent. There is no loss or gain in the whole transaction. The cost price of the watch on which the shopkeeper gains, is

a) Rs.390

b) Rs.380

c) Rs.370

d) Rs.360

Answer: (d)

Let the cost price of first watch which sold on 16 per cent be x.

Then cost price of second watch = (840 - x )

According to the question,

$x × 116/100 + (800 - x) × 88/100$ = 840

$116/100 + {73920 - 88x}/100$ = 840

116x - 88x = 84000 - 73920

28x = 10080 ⇒ x = $10080/28$ = Rs.360

Question : 13 [SSC SO 2005]

A man sold two watches for Rs.240 each. On one he gains 20% and incurs a loss of 20% on another. What is his gain or loss per cent in this transaction ?

a) 4% loss

b) 4% profit

c) 2% loss

d) 1% profit

Answer: (a)

Using Rule 10,

Required loss % = $(20)^2/100 = 400/100$ = 4%

Question : 14 [SSC SO 2007]

Two-third of a consignment was sold at a profit of 5% and the remainder at a loss of 2%. If the total profit was Rs.400, then the value of the consignment was

a) Rs.16,500

b) Rs.16,000

c) Rs.15,500

d) Rs.15,000

Answer: (d)

Let the price of the sent items be x.

According to the question,

${2x}/3 × 5/100 - x/3 × 2/100$ = 400

${10x}/3 - {2x}/3$ = 400 × 100

${8x}/3 = 40000 ⇒ x = {40000 × 3}/8$ = Rs.15000

Question : 15 [SSC CGL Tier-I 2013]

A person bought two bicycles for Rs.1600 and sold the first at 10% profit and the second at 20% profit. If he sold the first at 20% profit and the second at 10% profit, he would get Rs.5 more. The difference of the cost price of the two bicycles was :

a) Rs.75

b) Rs.25

c) Rs.40

d) Rs.50

Answer: (d)

If the C.P. of first cycle be x, then C.P. of second cycle = Rs.(1600 - x ).

Then, ${x × 120}/100 + {(1600 - x) × 110}/100$

$- {x × 110}/100 - {(1600 - x) × 120}/100$ = 5

12x + 17600 - 11x - 11x - 19200 + 12 x = 50

2x = 50 + 19200 - 17600

2x = 1650 ⇒ x = 825

C.P. of second cycle

= 1600 - 825 = Rs.775

Difference = 825 - 775 = Rs.50

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