Practice 2 articles sold in diff rates - quantitative aptitude Online Quiz (set-1) For All Competitive Exams
Q-1) A man sells two chairs at Rs.120 each and by doing so gains 25% on one chair and loses 25% on the other. His loss on the whole in Rs. is
(a)
(b)
(c)
(d)
C.P. of first chair = $100/125 × 120$ = Rs.96
C.P. of second chair = $100/75 × 120$ = Rs.160
∴ Loss = 160 + 96 - 240 = Rs.16
Q-2) A shopkeeper sells an article at 15% gain. Had he sold it for Rs.18 more, he would have gained 18%. The cost price (in Rs.) of the article is
(a)
(b)
(c)
(d)
C.P. of article be Rs.x
(118 - 115)% of x = 18
${x × 3}/100 =18 ⇒ x = {18 ×100}/3$ = Rs.600
Using Rule 11,A man sells his items at a profit/loss of x%.If he had sold it for Rs. R more,he would have gained/lost y%. Then. C.P. of items = $R/{(y ± x)}$ × 100'+' = When one is profit and other is loss.' - ' = When both are either profit or loss.
Here, x = 15%, R= 18, y = 18%
C.P. = ${R × 100}/{y - x}$
= ${18 ×100}/{18 -15}$ = Rs.600
Q-3) A person bought two bicycles for Rs.1600 and sold the first at 10% profit and the second at 20% profit. If he sold the first at 20% profit and the second at 10% profit, he would get Rs.5 more. The difference of the cost price of the two bicycles was :
(a)
(b)
(c)
(d)
If the C.P. of first cycle be x, then C.P. of second cycle = Rs.(1600 - x ).
Then, ${x × 120}/100 + {(1600 - x) × 110}/100$
$- {x × 110}/100 - {(1600 - x) × 120}/100$ = 5
12x + 17600 - 11x - 11x - 19200 + 12 x = 50
2x = 50 + 19200 - 17600
2x = 1650 ⇒ x = 825
C.P. of second cycle
= 1600 - 825 = Rs.775
Difference = 825 - 775 = Rs.50
Q-4) A man had 100 kgs of sugar, part of which he sold at 7% profit and rest at 17% profit. He gained 10% on the whole. How much did he sell at 7% profit ?
(a)
(b)
(c)
(d)
Let the amount of sugar sold at 7% profit be x kg. and let C.P. per kg be Rs.1.
Total C.P. = Rs.100
Total S.P. = 107% of x + 117% of (100 - x )
= 1.07x + 1.17 (100 - x )
= 1.07x + 117 - 1.17x = 117 - 0.1x
117 - 0.1x = 110% of 100
0.1x = 117 - 110 = 7
x = $7/{0.1}$ = 7 × 10 = 70 kg.
Q-5) The total cost price of two watches is Rs.840. One is sold at a profit of 16 per cent and the other at a loss of 12 per cent. There is no loss or gain in the whole transaction. The cost price of the watch on which the shopkeeper gains, is
(a)
(b)
(c)
(d)
Let the cost price of first watch which sold on 16 per cent be x.
Then cost price of second watch = (840 - x )
According to the question,
$x × 116/100 + (800 - x) × 88/100$ = 840
$116/100 + {73920 - 88x}/100$ = 840
116x - 88x = 84000 - 73920
28x = 10080 ⇒ x = $10080/28$ = Rs.360
Q-6) A man bought two goats for Rs.1008. He sold one at a loss of 20% and other at a profit of 44%. If each goat was sold for the same price, the cost price of the goat which was sold at loss, was :
(a)
(b)
(c)
(d)
If x and y be the cost price of two goats, then,
80% of x = 144% of y
$x/y = 144/80 = 9/5$
i.e., x : y = 9 : 5
Sum of the ratios = 9 + 5 = 14
Cost of first goat = Rs.$(9/14 × 1008)$ = Rs.648
Q-7) Kewal sells two tape recorders at the same price. On one, he gains 10% and on the other he loses 10%. The total gain or loss in the transaction is
(a)
(b)
(c)
(d)
Using Rule 10,
Note : When S.P. of each of two items is same, on one of them there is x% loss and on the other there is x% gain, then there isalways a loss given by (x% of x)% = $x^2/100%$
The required loss % = ${10 × 10}/100$ = 1 %
Q-8) A man sold two watches for Rs.240 each. On one he gains 20% and incurs a loss of 20% on another. What is his gain or loss per cent in this transaction ?
(a)
(b)
(c)
(d)
Using Rule 10,
Required loss % = $(20)^2/100 = 400/100$ = 4%
Q-9) A dealer sold two types of goods for Rs.10,000 each. On one of them, he lost 20% and on the other he gained 20%. His gain or loss per cent in the entire transaction was
(a)
(b)
(c)
(d)
Using Rule 10,
Here, S.P. is same. Hence there is always a loss.
Loss per cent = ${20 × 20}/100$ = 4%
Q-10) A man sold two articles at Rs.375 each. On one, he gains 25% and on the other, he loses 25%. The gain or loss% on the whole transaction is
(a)
(b)
(c)
(d)
Using Rule 10,If a man sells two similar objects, one at a loss of x% and another at a gain of x%, then he always incurrs loss in this transaction and loss% is $x^2/100%$
Here, both the articles are sold at the same price.
Hence, there is always loss.
Loss per cent= ${25 × 25}/100 = 25/4 = 6{1}/4$%