model 11 ratio & partnership Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CHSL 2013]

At the beginning of a partnership business, the capital of B was $3/2$ times that of A. After 8 months B withdrew $1/2$ of his capital and after 10 months A withdrew $1/4$ th of his capital. At the end of the year, if the profit incurred is Rs.53,000, find the amount received by A.

a) Rs.32,000

b) Rs.30,800

c) Rs.30,000

d) Rs.23,000

Answer: (d)

Initially, A’s capital = Rs.x

B’s capital = Rs.${3x}/2$

Ratio of the equivalent capitals of A and B for 1 month

= $(x × 10 + {3x}/4 × 2) : ({3x}/2 × 8 + {3x}/4 × 4)$

= $(10x + {3x}/2)$ : (12x + 3x) = 23 : 30

A’ share = $23/53$ × 53000 = Rs.23000

Question : 2 [SSC SO 2007]

7 kg of tea costing Rs.280 per kg is mixed with 9 kg of tea costing Rs.240 per kg. The average price per kg of the mixed tea is

a) Rs.257.50

b) Rs.255.80

c) Rs.267.20

d) Rs.267.50

Answer: (a)

Average price of blended tea

= ${280 × 7 + 240 × 9}/16 = {1960 + 2160}/16$

= $4120/16$ = Rs.257.50 kg

Question : 3 [SSC CGL Tier-II 2012]

Rs.864 is divided among A, B and C such that 8 times A’s share is equal to 12 times B’s share and also equal to 6 times C’s share. How much did B get ?

a) Rs.192

b) Rs.399

c) Rs.288

d) Rs.72

Answer: (a)

8A = B × 12 = 6C

${8A}/24 = {12B}/24 = {6C}/24$

$A/3 = B/2 = C/4$

A : B : C = 3 : 2 : 4

B’s share = $2/{3 + 2 + 4}$ × 864

=$2/9 × 864$ = Rs.192

Question : 4 [SSC CGL Prelim 2004]

In what ratio must a grocer mix tea at Rs.60 a kg, and Rs.65 a kg, so that by selling the mixture at Rs.68.20 a kg, he may gain 10%?

a) 3 : 4

b) 3 : 2

c) 3 : 5

d) 4 : 5

Answer: (b)

S.P. of 1 kg mixture = Rs.68.20, Gain = 10%

C.P. of 1 kg mixture = Rs.$(68.20 × 100/110)$ = Rs.62

By the rule of alligation,

∴ Required ratio = 3 : 2

Question : 5 [SSC CGL 2013]

A shopkeeper earns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is

a) 25 : 37

b) 99 : 125

c) 50 : 61

d) 45 : 56

Answer: (d)

Let the printed price of the book be x.

Selling price = 90% of x = $x × 90/100 = {9x}/10$

If the CP of the book be y, then

y × $112/100 = {9x}/10$

$y/x =9/10 × 100/112 = 45/56$ or 45 : 56

IMPORTANT quantitative aptitude EXERCISES

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