model 7 sold at loss Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CHSL 2015]

A merchant has 1000 kg sugar, part of which sells at 8% profit and the rest at 18% profit. He gain 14% on the whole. The quantity sold at 8% profit is :

a) 560 kg.

b) 400 kg.

c) 600 kg.

d) 640 kg.

Answer: (b)

Let the quantity of sugar at 8% profit be x kg.

Quantity of sugar sold at 18% = (100 - x) kg

According to the question,

$x × 108/100 + (1000 - x) × 118/100$

= ${1000 × 114}/100$

108x + 118000 - 118x = 114000

10x = 118000 - 114000

10x = 4000 ⇒ x = 400 kg

Question : 2 [SSC CHSL 2012]

A book vendor sold a book at a loss of 20%. Had he sold it for Rs.108 more, he would have earned a profit of 30%. Find the cost price of the book ?

a) Rs.216

b) Rs.432

c) Rs.648

d) Rs.240

Answer: (a)

If the cost price of the book be Rs.x, then

${x × 80}/100 + 108 = {x × 130}/100$

${5x}/10 = 108 ⇒ x = Rs.216$

Using Rule 11

Here, x = 20%, R= Rs.108, y=30%

C.P. = ${R × 100}/{y + x}$

= ${108 × 100}/{30 + 20}$

= $10800/50$ = Rs.216

Question : 3 [SSC CGL Tier-II 2017]

The profit earned by a shopkeeper by selling a bucket at a gain of 8% is Rs.28 more than when he sells it at a loss of 8%. The cost price (in Rupees) of the bucket is

a) 170

b) 165

c) 190

d) 175

Answer: (d)

Let the C.P. of bucket be Rs.x.

According to the question,

${108x}/100 - {92x}/100$ = 28

${16x}/100$ = 28

$x = {28 × 100}/16$ = Rs.175

Question : 4 [SSC CGL Prelim 2007]

A book seller sells a book at a profit of 10%. If he had bought it at 4% less and sold it for Rs.6 more, he would have gained 18$3/4%$. The cost price of the book is

a) Rs.130

b) Rs.160

c) Rs.140

d) Rs.150

Answer: (d)

Let the CP of the book be Rs.x.

Initial SP = $110/100 × x = 1.1 x$

New CP = 0.96 x

New SP = $(100 + 75/4)%$ of 0.96x

=$475/400 × 0.96x = 1.14 x$

Therefore, 1.14 x –1.1x = 6

0.04 x = 6

$x = 6/{0.04} = 600/4 = 150$

CP = Rs.150

Question : 5 [SSC DEO 2009]

When an article is sold at a gain of 20%, it yields Rs.60 more than when it is sold at a loss of 20%. The cost price of the article is

a) Rs.200

b) Rs.120

c) Rs.150

d) Rs.140

Answer: (c)

Let the CP of the article be Rs.x.

${120x}/100 - {80x}/100 = 60$

40x = 60 × 100

$x = {60 × 100}/40$ = Rs.150

Using Rule 11,

Here, x = 20%, R= Rs.60, y= 20%

C.P. = ${R × 100}/{y + x}$

= ${60 × 100}/{20 + 20}$

= $6000/40$ = Rs.150

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