model 3 gain/loss % with C.P/S.P Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CGL Tier-I 2016]

If by selling an article for Rs. 390 a shopkeeper gains 20%, then the cost price is

a) Rs. 350

b) Rs. 325

c) Rs. 300

d) Rs. 370

Answer: (b)

Let the C.P. of article be Rs.x.

According to the question,

$x × 120/100$ = 390

$x = {390 × 100}/120$ = Rs.325

Question : 2 [SSC CAPFs SI 2013]

A man sold 250 chairs and had a gain equal to selling price of 50 chairs. His profit per cent is :

a) 50%

b) 25%

c) 15%

d) 20%

Answer: (b)

S.P. of 250 chairs - C.P. of 250 chairs

= S.P. of 50 chairs

S.P. of 200 chairs = C.P. of 250 chairs

profit%= ${250 - 200}/200 × 100 = 25%$

Using Rule 9,

Here, x = 250, y = 50

∴ Profit% = ${y × 100}/{x - y}$

= ${50 × 100}/{250 - 50} = 50/2$ = 25%

Question : 3 [SSC CGL Tier-II 2016]

Last year Mr. A bought two paintings. This year he sold them for Rs. 20,000 each. On one, he made a 25% profit and on the other he had a 25% loss. Then his net profit or loss is

a) He earned more than Rs. 2000

b) He lost less than Rs. 2000

c) He earned less than Rs. 2000

d) He lost more than Rs. 2000

Answer: (d)

C.P. of first painting

= ${20000 × 100}/125$ = Rs.16000

C.P. of second painting

= ${20000 × 100}/75$ = Rs.26666.7

Loss = Rs.(16000 + 26666.7 - 40000)

= Rs.2666.7

Question : 4 [SSC CGL Prelim 2003]

Profit after selling a commodity for 524 is the same as loss after selling it for 452. The cost price of the commodity is

a) 488

b) 500

c) 485

d) 480

Answer: (a)

Let the cost price of the commodity = Rs.x

According to the question,

524 - x = x - 452

or 2x = 524 + 452

or 2x = 976 or $x =976/2 = 488$

∴ The required price = Rs.488

Question : 5 [SSC CHSL 2010]

A merchant sold an article for 75 at a profit percent equal to its cost price. The cost price of the article was :

a) 54

b) 50

c) 60

d) 45

Answer: (b)

Using Rule 3,

Let the cost price of article be Rs.x.

$({100 + x}/100)$ of x = 75

$x^2 + 100x - 7500$ = 0

$x^2 + 150x - 50x - 7500$ = 0

x (x + 150) - 50 (x + 150) = 0

(x - 50) (x + 150) = 0

x = 50 as x can't be negative

IMPORTANT quantitative aptitude EXERCISES

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