model 7 marks scored in examinations Practice Questions Answers Test with Solutions & More Shortcuts
percentage PRACTICE TEST [11 - EXERCISES]
model 1 simple percentage questions
model 2 net increase or decrease in %
model 3 reducing & exceeding prices
model 4 x & y comparison
model 5 income & expenditure
model 6 consumption & remaining
model 7 marks scored in examinations
Model 8 population based
model 9 voters & election
model 10 percentage with allegations & mixture
model 11 percentage with ratios
Question : 26 [SSC GL Tier-II 2012]
In an examination, 52% students failed in Hindi and 42% in English. If 17% failed in both the subjects, what percentage of students passed in both the subjects ?
a) 23%
b) 33%
c) 18%
d) 38%
Answer »Answer: (a)
Let the total number of students = 100
Number of students who failed in Hindi or English or both
= 52 + 42 – 17 = 77
Number of students who passed in both subjects
= 100 – 77 = 23%
Required percentage = 23
Using Rule 23,
a = 52%, b = 42%, c = 17%
Passed candidates = 100 – (52 + 42 – 17)
= 100 – (94 – 17) = 100 – 77 = 23%
Question : 27 [SSC SO 2007]
In a test a student got 30% marks and failed by 25 marks. In the same test another student got 40% marks and secured 25 marks more than the essential minimum pass marks. The maximum marks for the test were
a) 500
b) 480
c) 580
d) 400
Answer »Answer: (a)
Let the maximum marks in the examination = x.
According to the question,
${40x}/100 - {30x}/100 = 50$
${10x}/100 = 50$
$x = {50 × 100}/10 = 500$
Using Rule 22,
m = 30%, n = 40%, p = 25 and q = 25
Maximum marks = $100/{(n - m)} × (p + q)$
= $100/{(40 - 30)} × (25 + 25) = 500$
Question : 28 [SSC CPO S.I.2010]
In an examination, a student had to obtain 33% of the maximum marks to pass. He got 125 marks and failed by 40 marks. The maximum marks were
a) 800
b) 600
c) 1000
d) 500
Answer »Answer: (d)
Let the maximum marks be x.
${x × 33}/100 = 125 + 40 = 165$
x = ${165 × 100}/33 =500$
Using Rule 24,
a = 33%, b = 125, c = 40
Maximum marks = ${(b + c)}/a × 100$
= ${(125 + 40)}/33 × 100$
= ${165 × 100}/35 = 500$
Question : 29 [SSC CGL Prelim 2004]
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. The marks obtained by them are :
a) 41, 32
b) 43, 34
c) 39, 30
d) 42, 33
Answer »Answer: (d)
Let the marks obtained by first student be x.
Marks obtained by second student = x + 9
Sum of their marks = 2x + 9
As given, x + 9 = 56% of (2x + 9)
x + 9 = $56/100 × (2x + 9)$
$x + 9 = 14/25 × (2x + 9)$
25x + 225 = 28x + 126
3x = 225 – 126 ⇒ $x = 99/3 = 33$
Marks obtained are 42 and 33.
Question : 30 [SSC CHSL 2011]
In an examination in which full marks were 500, A got 10% less than B. B got 25% more than C. C got 20% less than D. If A got 360 marks, what percentage of full marks was obtained by D ?
a) 50%
b) 80%
c) 60%
d) 90%
Answer »Answer: (b)
A = 360;
B = ${360 × 100}/90 = 400$
C = ${400 × 100}/125 = 320$
D = ${320 × 100}/80 = 400$
Required percentage = $400/500 ×100 = $80%
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model 7 marks scored in examinations Shortcuts »
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Click to Start..percentage Shortcuts and Techniques with Examples
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model 1 simple percentage questions
Defination & Shortcuts … -
model 2 net increase or decrease in %
Defination & Shortcuts … -
model 3 reducing & exceeding prices
Defination & Shortcuts … -
model 4 x & y comparison
Defination & Shortcuts … -
model 5 income & expenditure
Defination & Shortcuts … -
model 6 consumption & remaining
Defination & Shortcuts … -
model 7 marks scored in examinations
Defination & Shortcuts … -
Model 8 population based
Defination & Shortcuts … -
model 9 voters & election
Defination & Shortcuts … -
model 10 percentage with allegations & mixture
Defination & Shortcuts … -
model 11 percentage with ratios
Defination & Shortcuts …
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