model 7 marks scored in examinations Practice Questions Answers Test with Solutions & More Shortcuts
percentage PRACTICE TEST [11 - EXERCISES]
model 1 simple percentage questions
model 2 net increase or decrease in %
model 3 reducing & exceeding prices
model 4 x & y comparison
model 5 income & expenditure
model 6 consumption & remaining
model 7 marks scored in examinations
Model 8 population based
model 9 voters & election
model 10 percentage with allegations & mixture
model 11 percentage with ratios
Question : 1 [SSC CGL Prelim 2004]
In a group of students, 70% can speak English and 65% can speak Hindi. If 27% of the students can speak none of the the two languages, then what per cent of the group can speak both the languages ?
a) 28%
b) 62%
c) 23%
d) 38%
Answer »Answer: (b)
Let total number of students = 100
27 students speak none of the two languages.
It means only 73 students speak either Hindi or English or both.
Let x students speak both languages.
∴ 73 = 70 – x + x + 65 – x
x = 70 + 65 – 73 = 62%
Question : 2 [SSC CGL Prelim 2003]
A candidate secured 30% marks in an examination and failed by 6 marks. Another secured 40% marks and got 6 marks more than the bare minimum to pass. The maximum marks are
a) 100
b) 120
c) 180
d) 150
Answer »Answer: (b)
Difference of percentage = (40 – 30)% = 10%
Difference of marks = 6 + 6= 12
Since,10% of total marks = 12
Total marks = ${12 × 100}/10 = 120$
Using Rule 22,
Here, m = 30%, n = 40%, p = 6, q = 6.
Maximum Marks = $100/{(n - m)} × (p + q)$
= $100/{(40 - 30)} × (6 + 6)$
= $100/10 × 12 = 120$
Question : 3
In an examination, there were 1000 boys and 800 girls. 60% of the boys and 50% of the girls passed. Find the percent of the candidates failed ?
a) 44.4%
b) 48.4%
c) 49.6%
d) 46.4%
Answer »Answer: (a)
Total candidates = 1000 + 800 = 1800
The candidates who are passed
= $1000 × 60/100 + 800 × 50/100$
= 600 + 400 = 1000
The number of candidates who failed = 1800 – 1000 = 800
Required percent = $800/1800 × 100 = 44.4%$
Using Rule 25,
Percentage of passed students = $({B.b + G.g}/{B + G})%$
= ${1000 × 60 + 800 × 50}/{1000 + 800}$
= ${60000 + 40000}/1800$
= $100000/1800 = 500/9 = 55.5$
Percentage of failed students = 100 – 55.5 = 44.4%
Question : 4 [SSC CPO S.I.2003]
A student has to obtain 33% of total marks to pass. He got 25% of total marks and failed by 40 marks. The number of total marks is
a) 500
b) 300
c) 1000
d) 800
Answer »Answer: (a)
Let the total marks be x.
According to the question,
25% of x + 40 = 33% of x
(33 – 25)% of x = 40
8% of x = 40
x = ${40 × 100}/8$ = 500
Question : 5
For an examination it is required to get 36 % of maximum marks to pass. A student got 113 marks and failed by 85 marks. The maximum marks for the examination are :
a) 565
b) 550
c) 620
d) 500
Answer »Answer: (b)
Let maximum marks be x, then,
${36 × x}/100 = 113 + 85 = 198$
$x = {198 × 100}/36 = 550$
Using Rule 24,
a = 36%, b = 113, c = 85
Maximum marks = ${(b + c)}/a × 100$
= ${(113 + 85)}/36 × 100$
= $198/36 × 100$ = 550
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model 7 marks scored in examinations Shortcuts »
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Click to Start..percentage Shortcuts and Techniques with Examples
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model 1 simple percentage questions
Defination & Shortcuts … -
model 2 net increase or decrease in %
Defination & Shortcuts … -
model 3 reducing & exceeding prices
Defination & Shortcuts … -
model 4 x & y comparison
Defination & Shortcuts … -
model 5 income & expenditure
Defination & Shortcuts … -
model 6 consumption & remaining
Defination & Shortcuts … -
model 7 marks scored in examinations
Defination & Shortcuts … -
Model 8 population based
Defination & Shortcuts … -
model 9 voters & election
Defination & Shortcuts … -
model 10 percentage with allegations & mixture
Defination & Shortcuts … -
model 11 percentage with ratios
Defination & Shortcuts …
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