find distance only section 4 Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC (10+2) Level DEO & LDC 2011]

A, B, C, D and E are standing in a line facing North. E is standing 40 metres left to B. A is standing 20 metres left to C. D is standing 20 metres right to E and 50 metres right to C. What is the distance between A and D ?

a) 60 metres

b) 80 metres

c) 50 metres

d) 70 metres

Answer: (d)

direction-and-distance-verbal-reasoning

AD = (20 + 30 + 20)m = 70m

Question : 22 [SSC (10+2) Level DEO & LDC 2010]

Rama is standing at a point facing north. He walks 10 km straight, turns left and walks another 15 km straight and finally turns left and walks 10 km. How far is he from the starting points now ?

a) 5 km

b) 15 km

c) 10 km

d) 12 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance = 15 km

Question : 23 [SSC (10+2) Level DEO & LDC 2011]

Mohan travelled from point ‘A’ straight to ‘B’ at a distance of 8 m. He turned right and walked 4m, again turned to his right and walked 8 m. Finally he turned to his right and walked 3 m. How far he was from his starting point?

a) 3 m

b) 4 m

c) 8 m

d) 1 m

Answer: (d)

direction-and-distance-verbal-reasoning

Required distance = 1 km

Question : 24 [SSC CHSL LDC, DEO & PA/SA 2015]

After going 80 m from his house towards east, a person turns left and goes 20 m, then turns right and moves 100 m, then turns left and goes 60 m, then turns right and goes 120m to reach the park. What is the distance between his house and the park?

a) 120 metre

b) 300 metre

c) 280 metre

d) 220 metre

Answer: (b)

direction-and-distance-verbal-reasoning

AF = $√{FG^2 + AG^2}$

= $√{80^2 + 300^2}$

= $√{6400+ 90000}$

= $√{96400}$ = 310.48

» 300 metres

Question : 25 [SSC GL Tier-I 2014]

Raju cycled 10 km South from his house, turned right and went 5 km and again turned right and cycled 10 km and then turned left and cycled 10 km. How many kilometres will he have to cycle back to reach his house ?

a) 5 km

b) 15 km

c) 10 km

d) 20 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

= AE = AD + DE

= (5 + 10) km

= 15 km

IMPORTANT verbal reasoning EXERCISES

find distance only section 4 Online Quiz

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920 direction & distance sense test based verbal reasoning section 4 question answer with explanation pdf

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