find distance only section 4 Detailed Explanation And More Example
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The following question based on direction & distance sense test topic of verbal reasoning
(a) 60 metres
(b) 80 metres
(c) 50 metres
(d) 70 metres
The correct answers to the above question in:
Answer: (d)
AD = (20 + 30 + 20)m = 70m
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Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers
Question : 1
Rama is standing at a point facing north. He walks 10 km straight, turns left and walks another 15 km straight and finally turns left and walks 10 km. How far is he from the starting points now ?
a) 5 km
b) 15 km
c) 10 km
d) 12 km
Answer »Answer: (b)
Required distance = 15 km
Question : 2
Mohan travelled from point ‘A’ straight to ‘B’ at a distance of 8 m. He turned right and walked 4m, again turned to his right and walked 8 m. Finally he turned to his right and walked 3 m. How far he was from his starting point?
a) 3 m
b) 4 m
c) 8 m
d) 1 m
Answer »Answer: (d)
Required distance = 1 km
Question : 3
After going 80 m from his house towards east, a person turns left and goes 20 m, then turns right and moves 100 m, then turns left and goes 60 m, then turns right and goes 120m to reach the park. What is the distance between his house and the park?
a) 120 metre
b) 300 metre
c) 280 metre
d) 220 metre
Answer »Answer: (b)
AF = $√{FG^2 + AG^2}$
= $√{80^2 + 300^2}$
= $√{6400+ 90000}$
= $√{96400}$ = 310.48
» 300 metres
Question : 4
Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?
a) 50 metres
b) 30 metres
c) 20 metres
d) 60 metres
e) None of these
Answer »Answer: (d)
The movements of Gaurav are as shown in Figure.
Clearly, Gaurav's distance from his initial position
P = PX = (PS + SX) = (QR + SX)
= (40 + 20)m = 60m.
Question : 5
travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?
a) 50 metres
b) 20 metres
c) 10 metres
d) 70 metres
e) None of these
Answer »Answer: (c)
The movements of Raj are as shown in the figure,
(X to Y, Y to A, A to B, B to C)
∴ Raj's distnace from the starting point X
= XC = (XY - YC)
= (XY - BA)
= (80 - 70) = 10m.
Question : 6
Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?
a) 10
b) 40
c) 0
d) 20
Answer »Answer: (a)
The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).
So, Kashish’s distance from his original position A = AE
AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.
GET direction & distance sense test PRACTICE TEST EXERCISES
find directions only
find distance only
find both direction & distance
find directions only section 2
find directions only section 3
find directions only section 4
find directions only section 5
find directions only section 6
find distance only section 2
find distance only section 3
find distance only section 4
find distance only section 5
find distance only section 6
find both direction & distance section 2
find both direction & distance section 3
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