find distance only section 4 Detailed Explanation And More Example

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The following question based on direction & distance sense test topic of verbal reasoning

Questions : A, B, C, D and E are standing in a line facing North. E is standing 40 metres left to B. A is standing 20 metres left to C. D is standing 20 metres right to E and 50 metres right to C. What is the distance between A and D ?

(a) 60 metres

(b) 80 metres

(c) 50 metres

(d) 70 metres

The correct answers to the above question in:

Answer: (d)

direction-and-distance-verbal-reasoning

AD = (20 + 30 + 20)m = 70m

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Read more type 2 section 4 mcqs Based Verbal Reasoning Questions and Answers

Question : 1

Rama is standing at a point facing north. He walks 10 km straight, turns left and walks another 15 km straight and finally turns left and walks 10 km. How far is he from the starting points now ?

a) 5 km

b) 15 km

c) 10 km

d) 12 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance = 15 km

Question : 2

Mohan travelled from point ‘A’ straight to ‘B’ at a distance of 8 m. He turned right and walked 4m, again turned to his right and walked 8 m. Finally he turned to his right and walked 3 m. How far he was from his starting point?

a) 3 m

b) 4 m

c) 8 m

d) 1 m

Answer: (d)

direction-and-distance-verbal-reasoning

Required distance = 1 km

Question : 3

After going 80 m from his house towards east, a person turns left and goes 20 m, then turns right and moves 100 m, then turns left and goes 60 m, then turns right and goes 120m to reach the park. What is the distance between his house and the park?

a) 120 metre

b) 300 metre

c) 280 metre

d) 220 metre

Answer: (b)

direction-and-distance-verbal-reasoning

AF = $√{FG^2 + AG^2}$

= $√{80^2 + 300^2}$

= $√{6400+ 90000}$

= $√{96400}$ = 310.48

» 300 metres

Question : 4

Gaurav walks 20 metres towards North. He then turns left and walks 40 metres. He again turns left and walks 20 metres. Further, he moves 20 metres after turning to the right. How far is he from his original position ?

a) 50 metres

b) 30 metres

c) 20 metres

d) 60 metres

e) None of these

Answer: (d)

direction-and-distance-verbal-reasoning

The movements of Gaurav are as shown in Figure.

Clearly, Gaurav's distance from his initial position

P = PX = (PS + SX) = (QR + SX)

= (40 + 20)m = 60m.

Question : 5

travelled from a point X straight to Y at a distance of 80 metres. He turned right and walked 50 metres, then again turned right and walked 70 metres. Finally, he turned right and walked 50 metres. How far is he from the starting point ?

a) 50 metres

b) 20 metres

c) 10 metres

d) 70 metres

e) None of these

Answer: (c)

direction-and-distance-verbal-reasoning

The movements of Raj are as shown in the figure,

(X to Y, Y to A, A to B, B to C)

∴  Raj's distnace from the starting point X

= XC = (XY - YC)

= (XY - BA)

= (80 - 70) = 10m.

Question : 6

Kashish goes 30 metres North, then turns right and walks 40 metres, then again turns right and walks 20 metres, then again turns right and walks 40 metres. How many metres is he from his original position?

a) 10

b) 40

c) 0

d) 20

Answer: (a)

direction-and-distance

The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E).

So, Kashish’s distance from his original position A = AE

AE = (AB – BE) = (AB – CD) = (30 – 20) m = 10 m.

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