find distance only Practice Questions Answers Test with Solutions & More Shortcuts

Question : 96 [SSC CGL Tier-I 2016]

Rohan walks a distance of 3 kms towards North, then turns to his left and walks for 2 kms. He again turns left and walks for 3 kms. At this point he turns to his left and walks for 3 kms. How far is he from the starting point?

a) 3 kms

b) 1 km

c) 5 kms

d) 2 kms

Answer: (b)

direction-and-distance-verbal-reasoning

AE = 1 km.

Question : 97 [SSC CGL Tier-1 2011]

Ganesh cycles towards SouthWest a distance of 8 m, then he moves towards East a distance of 20 m. From there he moves towards North-East a distance of 8 m, then he moves towards West a distance of 6 m. From there he moves towards North-East a distance of 2 m. Then he moves towards West a distance of 4 m and then towards South-West 2 m and stops at that point. How far is he from the starting point?

a) 10 m

b) 6 m

c) 12 m

d) 8 m

Answer: (a)

direction-and-distance-verbal-reasoning

AH = 20 – (4 + 6) = 10m

Question : 98

Satish starts from A and walks 2 km east upto B and turns southwards and walks 1 km upto C. At C he turns to east and walks 2 km upto D. He then turns northwards and walks 4 km to E. How far is he from his starting point?

a) 4 km

b) 6 km

c) 3 km

d) 5 km

Answer: (d)

direction-and-distance

AP = 2 + 2 = 4 km

PE = 4 – 1 = 3km

⇒ AE = $√{16 + 9}$ = 5km

Question : 99 [SSC Com Matric Level 2006]

A starts walking from a point P. A goes westward and covers a distance of 4 km and then turns to his right and walks 3 km. How far A is from the starting point?

a) 9 km

b) 5 km

c) 7 km

d) 2 km

Answer: (b)

direction-and-distance-verbal-reasoning

Required distance

= $√{PQ^2 + QR^2}$

= $√{4^2 + 3^2}$

= $√{16+ 9}$

= $√{25}$ = 5 km

Question : 100 [SSC Steno (Grade'C & D') 2010]

A man walks 7 km towards north before taking left turn and walks further 5 km. Then the takes left turn and walks 15 km. Finally he takes left turn again and walks 5 km. How much distance is he away from the starting point ?

a) 12 km

b) 22 km

c) 8 km

d) 15 km

Answer: (c)

direction-and-distance-verbal-reasoning

Required distance

= AF = BF– AB

= 15 – 7 = 8 km

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