type 10 conditional coding & decoding Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (a)

When condition is not applied, the coding is done as follows,

A → 4 E → 2 I → @ M → # V → 7 H → $.

But here the second letter is a vowel and the last letter is a consonant,

Therefore  condition (ii) is applied here.

As condition (ii) is applied here, both the second and the last letters are to be coded as 8.

A → 4 E → 8 I → @ M → # V → 7 H → 8

Hence, code for AEIMVH ⇒ 48@#78

Answer: (d)

When the condition is not applied, the coding is done as follows.

W → 5 M → # E → 2 I → @ J → 9 U → ©

But here the first letter is a consonant and the fourth letter is a vowel,

therefore condition (i) is applied here.

As condition (i) is applied here, both the first and the fourth letters are to be coded as the codes for the vowel.

W → @ M → # E → 2 I → @ J → 9 U → ©

Hence, code for WMEIJU ⇒ @#2@9©.

Answer: (e)

Here, none of the conditions is applied,

so the coding is done as follows. M → # B → * U → © V → 7 W → 5 E → 2

Hence, code for MBUVWE ⇒ #*©752

Answer: (a)

When the condition is not applied, the coding is done as follows.

T → 3 H → $ A → 4 F → 8 I → @ Q → 1

But here both the first and the last latter are consonants, therefore condition (iii) is applied here.

As condition (iii) as applied here, the codes for the first and the last letters are interchanged.

T → 1 H → $ A → 4 F → 8 I → @ Q → 3

Hence, code for THAFIQ ⇒ 1$48@3.

Answer: (d)

Here, none of the conditions is applied.

So the coding is done as follows. A → 4 J → 9 B → * M → # F → 8 U → ©

Hence, code for AJBMFU ⇒ 49*#8©.