type 10 conditional coding & decoding Detailed Explanation And More Example

Answer: (d)

Here, none of the conditions is applied.

So the coding is done as follows. A → 4 J → 9 B → * M → # F → 8 U → ©

Hence, code for AJBMFU ⇒ 49*#8©.

Answer: (d)

When no condition is applied, the coding is done as follows.

E → # M → % I → 9 R → 7 D → 8 P → *

But here the first letter is a vowel and the fourth letter is a consonant,

therefore condition (ii) is applied.

As condition (ii) is applied here, both the first and the fourth letters are to be coded as the code for the vowel.

E → @ M → % I → 9 R → # D → 8 P → *

Hence, code for EMIRDP ⇒ #%9#8*.

Answer: (e)

When no condition is applied, coding is done as follows. P → * Q → 4 I → 9 M → % H → © Z © 1

But here the first letter is a consonant and the third letter is a vowel, therefore condition (i) is applied.

As condition (i) is applied here, the codes for first and third letters are to be interchanged.

P → 9 Q → 4 I → * M → % H → © Z → 1

Hence, code for PQIMHZ ⇒ 94*%©1.

Answer: (e)

Here, none of the conditions is applied,

so the coding is done as follows. M → # B → * U → © V → 7 W → 5 E → 2

Hence, code for MBUVWE ⇒ #*©752

Answer: (d)

When the condition is not applied, the coding is done as follows.

W → 5 M → # E → 2 I → @ J → 9 U → ©

But here the first letter is a consonant and the fourth letter is a vowel,

therefore condition (i) is applied here.

As condition (i) is applied here, both the first and the fourth letters are to be coded as the codes for the vowel.

W → @ M → # E → 2 I → @ J → 9 U → ©

Hence, code for WMEIJU ⇒ @#2@9©.

Answer: (a)

When condition is not applied, the coding is done as follows,

A → 4 E → 2 I → @ M → # V → 7 H → $.

But here the second letter is a vowel and the last letter is a consonant,

Therefore  condition (ii) is applied here.

As condition (ii) is applied here, both the second and the last letters are to be coded as 8.

A → 4 E → 8 I → @ M → # V → 7 H → 8

Hence, code for AEIMVH ⇒ 48@#78