Model 4 Train Vs Pole/Signal Post/Man Practice Questions Answers Test with Solutions & More Shortcuts
trains PRACTICE TEST [6 - EXERCISES]
Model 1 Train Vs Train in same direction
Model 2 Train Vs Train in opposite direction
Model 3 Train Vs Bridge/Platform
Model 4 Train Vs Pole/Signal Post/Man
Model 5 Train Vs Both platform and a man/a pole
Model 6 Change in speed Vs Change with time travel
Question : 21 [SSC CGL Tier-II 2014]
A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?
a) 15 seconds
b) 17 seconds
c) 18 seconds
d) 20 seconds
Answer »Answer: (d)
Using Rule 1,
Speed of train = 54 kmph
= $({54 × 5}/18)$ m/sec = 15 m/sec
Required time = $\text"Length of trains"/ \text"Speedof train"$
= $300/15$ = 20 seconds
Question : 22 [SSC CGL Prelim 2005]
If a train, with a speed of 60 km/ hr, crosses a pole in 30 seconds, the length of the train (in metres) is :
a) 900
b) 750
c) 500
d) 1000
Answer »Answer: (c)
Using Rule 1,
Speed of train = 60 kmph
= 60 × $5/18 = 50/3$ m/sec
Length of train = Speed × Time
= $50/3 × 30$ = 500 m
Question : 23 [SSC CHSL 2015]
A train is 250m long. If the train takes 50 seconds to cross a tree by the railway line, then the speed of the train in km/hr is :
a) 9
b) 5
c) 18
d) 10
Answer »Answer: (c)
Using Rule 1,
Speed of train = $\text"Length of train"/ \text"Time taken in crossing"$
= $250/50$ = 5 m/sec.
= $(5 × 18/5)$ kmph = 18 kmph
Question : 24 [SSC CGL Prelim 2000]
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr. in the direction of the moving train if the speed of the train is 63 km/hr ?
a) 30 sec
b) 40 sec
c) 45 sec
d) 25 sec
Answer »Answer: (a)
Using Rule 5,
Relative speed of train
= 63–3 = 60 kmph
= $60 × 5/18$ m / sec
Time = $\text"Length of train"/ \text"Relative Speed"$
= ${500 × 18}/{60 × 5}$ = 30 sec.
Question : 25 [SSC CGL Prelim 1999]
A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it will pass a man standing near the railway line is :
a) 11
b) 12
c) 15
d) 10
Answer »Answer: (b)
Using Rule 1,
If a train crosses an electric pole, a sitting/standing man, km or milestone etc. then distance = Length of the train.
Then, Length of train = Speed × Time And Time = $\text"Length of train"/\text"Speed"$
and Speed = $\text"Length of train"/\text"Time"$
In this situation, the train covers it length.
Required time = $100/{30 × 1000}$ hr.
= ${100 × 60 × 60}/{30 × 1000}$ = 12 seconds
IMPORTANT quantitative aptitude EXERCISES
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Top 399+ Trains Based Time and Distance MCQs For BANK SSC »
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New 500+ Aptitude Problems on Train For All BANK SSC Exam »
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Top 499+ Aptitude MCQs on Trains Crossing Bridge/Platform »
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New 500+ Aptitude MCQs on Train Crossing Pole/Post or Man »
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Top 499+ Trains Problems Using Time and Distance For SSC »
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Top 489+ Time And Distance MCQ Problems on Train For BANK »
Model 4 Train Vs Pole/Signal Post/Man Shortcuts »
Click to Read...Model 4 Train Vs Pole/Signal Post/Man Online Quiz
Click to Start..trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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