Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on trains topic of quantitative aptitude

Questions : If a train, with a speed of 60 km/ hr, crosses a pole in 30 seconds, the length of the train (in metres) is :

(a) 900

(b) 750

(c) 500

(d) 1000

The correct answers to the above question in:

Answer: (c)

Using Rule 1,

Speed of train = 60 kmph

= 60 × $5/18 = 50/3$ m/sec

Length of train = Speed × Time

= $50/3 × 30$ = 500 m

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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers

Question : 1

A train is 250m long. If the train takes 50 seconds to cross a tree by the railway line, then the speed of the train in km/hr is :

a) 9

b) 5

c) 18

d) 10

Answer: (c)

Using Rule 1,

Speed of train = $\text"Length of train"/ \text"Time taken in crossing"$

= $250/50$ = 5 m/sec.

= $(5 × 18/5)$ kmph = 18 kmph

Question : 2

How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr. in the direction of the moving train if the speed of the train is 63 km/hr ?

a) 30 sec

b) 40 sec

c) 45 sec

d) 25 sec

Answer: (a)

Using Rule 5,

Relative speed of train

= 63–3 = 60 kmph

= $60 × 5/18$ m / sec

Time = $\text"Length of train"/ \text"Relative Speed"$

= ${500 × 18}/{60 × 5}$ = 30 sec.

Question : 3

A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it will pass a man standing near the railway line is :

a) 11

b) 12

c) 15

d) 10

Answer: (b)

Using Rule 1, 

If a train crosses an electric pole, a sitting/standing man, km or milestone etc. then distance = Length of the train.
Then, Length of train = Speed × Time And Time = $\text"Length of train"/\text"Speed"$
and Speed = $\text"Length of train"/\text"Time"$

In this situation, the train covers it length.

Required time = $100/{30 × 1000}$ hr.

= ${100 × 60 × 60}/{30 × 1000}$ = 12 seconds

Question : 4

A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?

a) 15 seconds

b) 17 seconds

c) 18 seconds

d) 20 seconds

Answer: (d)

Using Rule 1,

Speed of train = 54 kmph

= $({54 × 5}/18)$ m/sec = 15 m/sec

Required time = $\text"Length of trains"/ \text"Speedof train"$

= $300/15$ = 20 seconds

Question : 5

A train is 125 m long. If the train takes 30 seconds to cross a tree by the railway line, then the speed of the train is :

a) 15 km/hr

b) 16 km/hr

c) 12 km/hr

d) 14 km/hr

Answer: (a)

Using Rule 1,

Speed = $\text"Distance"/ \text"Time"$

=$125/30$ = 41.6 m/s

4.16 m/s = 4.16 × $18/5$ = 15 km/hr

Question : 6

A train 240 metres in length crosses a telegraph post in 16 seconds. The speed of the train is

a) 52 km/hr

b) 54 km/hr

c) 56 km/hr

d) 50 km/hr

Answer: (b)

When a train crosses a pole it travels a distance equal to its length.

Speed of train

= $240/16$ = 15 m./sec.

= $(15 × 18/5)$ kmph = 54 kmph.

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