Model 4 Train Vs Pole/Signal Post/Man Practice Questions Answers Test with Solutions & More Shortcuts

Question : 1 [SSC CPO S.I.2003]

A man observed that a train 120 m long crossed him in 9 seconds. The speed (in km/hr) of the train was

a) 45

b) 48

c) 55

d) 42

Answer: (b)

Using Rule 1,

Speed of train

= $120/9 × 18/5$ = 48 kmph

Question : 2 [SSC CGL Tier-I 2010]

A train, 300m long, passed a man, walking along the line in the same direction at the rate of 3 km/hr in 33 seconds. The speed of the train is

a) 32 km/h

b) 32$8/11$ km/h

c) 35$8/11$ km/h

d) 30 km/h

Answer: (c)

Using Rule 5,

If the speed of the train be x kmph,

then relative speed = (x - 3) kmph.

or (x - 3) × $5/18$ m/sec

$300/{(x - 3) × 5/18 = 33$

5400 = 33 × 5 (x - 3)

360 = 11 (x - 3)

11x - 33 = 360

$x = 393/11 = 35{8}/11$ kmph

Question : 3 [SSC CGL Tier-II 2015]

If a man walks at the rate of 5 km/hour, he misses a train by 7 minutes. However if he walks at the rate of 6 km/hour, he reaches the station 5 minutes before the arrival of the train. The distance covered by him to reach the station is

a) 7 km

b) 6.25 km

c) 4 km

d) 6 km

Answer: (d)

Let the required distance be x km.

Difference of time = 7 + 5 = 12

minutes = $1/5$ hour

Time = $\text"Distance"/ \text"Speed"$

According to the question,

$x/5 - x/6 = 1/5$

${6x - 5x}/30 = 1/5$

$x/30 = 1/5$ ⇒ $x = 30/5$ = 6 km.

Question : 4 [SSC CGL Tier-I 2010]

A train, 240 m long crosses a man walking along the line in opposite direction at the rate of 3 kmph in 10 seconds. The speed of the train is

a) 75 kmph

b) 83.4 kmph

c) 86.4 kmph

d) 63 kmph

Answer: (b)

Using Rule 6,

Let 'a' metre long train is running with the speed 'x' m/s. A man is running in the opposite direction of train with the speed of 'y' m/s. Then, time taken by the train to cross the man = $(a/{(x + y)})$seconds.

If the speed of train be x kmph then,

Its relative speed = (x + 3) kmph

Time = $\text"Length of the train"/ \text"Relative speed"$

$10/3600 = {240/1000}/{(x + 3)} = 240/{1000(x + 3)}$

x + 3 = 86.4 ⇒ x = 83.4 kmph

Question : 5 [SSC CGL Prelim 2002]

A 75 metre long train is moving at 20 kmph. It will cross a man standing on the platform in

a) 14 seconds

b) 13.5 seconds

c) 15.5 seconds

d) 12 seconds

Answer: (b)

Using Rule 1,

Speed of train (in m/s)

= 20 × $5/18 = 50/9$ m/sec

Required time = $75/50 × 9$

= 13.5 seconds

IMPORTANT quantitative aptitude EXERCISES

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