Model 4 Train Vs Pole/Signal Post/Man Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6 [SSC CPO S.I.2006]

A passenger train 150m long is travelling with a speed of 36 km/ hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is

a) 15 sec

b) 18 sec

c) 20 sec

d) 10 sec

Answer: (c)

Using Rule 5,
Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t

Relative speed of train

= (36 - 9) kmph = 27 kmph

= ${27 × 5}/18$ m/sec = $15/2$ m/sec

Required time

= $\text"Length of the train"/ \text"Relative speed"$

= ${150 × 2}/15 = 20$ seconds

Question : 7 [SSC CHSL 2015]

A train passes an electrical pole in 20 seconds and passes a platform 250 m long in 45 seconds. Find the length of the train.

a) 200m

b) 300m

c) 250m

d) 400m

Answer: (a)

Using Rule 1,

If the length of train be x metre, then speed of train

= $x/20 = {x + 250}/45$

$x/4 = {x + 250}/9$

9x = 4x + 1000

9x - 4x = 1000

5x = 1000

x = $1000/5$ = 200 metre

Question : 8 [SSC CGL Prelim 1999]

A train 180 m long moving at the speed of 20 m/sec. over-takes a man moving at a speed of 10m/ sec in the same direction. The train passes the man in :

a) 9 sec

b) 18 sec

c) 27 sec

d) 6 sec

Answer: (b)

Using Rule 5,
Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t

Relative speed of man and train

= 20 - 10 = 10m/sec.

Required time = $180/10$ = 18 seconds

Question : 9 [SSC CGL Tier-I 2016]

The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is

a) 9 seconds

b) 6 seconds

c) 4 seconds

d) 8 seconds

Answer: (d)

Distance covered in crossing a pole

= Length of train Speed of train = 72 kmph

= $({72 × 5}/18)$ m./sec. = 20 m./sec.

Required time = $160/20$ = 8 seconds

Question : 10 [SSC CGL Tier-I 2016]

In what time will a 100 metre long train running with a speed of 50 km/hr cross a pillar ?

a) 72 seconds

b) 7.2 seconds

c) 70 seconds

d) 7.0 seconds

Answer: (b)

Speed of train = 50 kmph

= $({50 × 5}/18)$ m./sec. = $125/9$ m./sec.

Required time = $({100/125}/9)$ seconds

= $({100 × 9}/125)$ = 7.2 seconds

IMPORTANT quantitative aptitude EXERCISES

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