Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions
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The following question based on trains topic of quantitative aptitude
(a) 30 sec
(b) 40 sec
(c) 45 sec
(d) 25 sec
The correct answers to the above question in:
Answer: (a)
Using Rule 5,
Relative speed of train
= 63–3 = 60 kmph
= $60 × 5/18$ m / sec
Time = $\text"Length of train"/ \text"Relative Speed"$
= ${500 × 18}/{60 × 5}$ = 30 sec.
Discuss Form
Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers
Question : 1
A train 100m long is running at the speed of 30 km/hr. The time (in second) in which it will pass a man standing near the railway line is :
a) 11
b) 12
c) 15
d) 10
Answer »Answer: (b)
Using Rule 1,
If a train crosses an electric pole, a sitting/standing man, km or milestone etc. then distance = Length of the train.
Then, Length of train = Speed × Time And Time = $\text"Length of train"/\text"Speed"$
and Speed = $\text"Length of train"/\text"Time"$
In this situation, the train covers it length.
Required time = $100/{30 × 1000}$ hr.
= ${100 × 60 × 60}/{30 × 1000}$ = 12 seconds
Question : 2
A train is running at a speed of 90 km/hr. If it crosses a signal in 10 sec., the length of the train (in metres) is
a) 324
b) 900
c) 250
d) 150
Answer »Answer: (c)
Using Rule 1,
Speed of train = 90 kmph
= $({90 × 5}/18)$ metre/second
= 25 metre/second
If the length of the train be x then,
Speed of train
= $\text"Length of train"/ \text"Time taken in crossing the signal"$
25 = $x/10$ ⇒ x = 250 metre
Question : 3
In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hour ?
a) 5 seconds
b) 12.5 seconds
c) 3$5/4$ seconds
d) 2.5 seconds
Answer »Answer: (d)
Using Rule 1,
Speed of the train = 144 kmph
= $144 × 5/18$ = 40 m/s
When a train crosses a pole, it covers a distance equal to its own length.
The required time
= $100/40 = 5/2$ = 2.5 seconds.
Question : 4
A train is 250m long. If the train takes 50 seconds to cross a tree by the railway line, then the speed of the train in km/hr is :
a) 9
b) 5
c) 18
d) 10
Answer »Answer: (c)
Using Rule 1,
Speed of train = $\text"Length of train"/ \text"Time taken in crossing"$
= $250/50$ = 5 m/sec.
= $(5 × 18/5)$ kmph = 18 kmph
Question : 5
If a train, with a speed of 60 km/ hr, crosses a pole in 30 seconds, the length of the train (in metres) is :
a) 900
b) 750
c) 500
d) 1000
Answer »Answer: (c)
Using Rule 1,
Speed of train = 60 kmph
= 60 × $5/18 = 50/3$ m/sec
Length of train = Speed × Time
= $50/3 × 30$ = 500 m
Question : 6
A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone pole?
a) 15 seconds
b) 17 seconds
c) 18 seconds
d) 20 seconds
Answer »Answer: (d)
Using Rule 1,
Speed of train = 54 kmph
= $({54 × 5}/18)$ m/sec = 15 m/sec
Required time = $\text"Length of trains"/ \text"Speedof train"$
= $300/15$ = 20 seconds
trains Shortcuts and Techniques with Examples
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Model 1 Train Vs Train in same direction
Defination & Shortcuts … -
Model 2 Train Vs Train in opposite direction
Defination & Shortcuts … -
Model 3 Train Vs Bridge/Platform
Defination & Shortcuts … -
Model 4 Train Vs Pole/Signal Post/Man
Defination & Shortcuts … -
Model 5 Train Vs Both platform and a man/a pole
Defination & Shortcuts … -
Model 6 Change in speed Vs Change with time travel
Defination & Shortcuts …
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