model 6 sold in circular path Practice Questions Answers Test with Solutions & More Shortcuts

Question : 6 [SSC CHSL 2012]

A sells an article to B at a gain of 10%, B sells it to C at a gain of 5%. If C pays Rs.462 for it, what did it cost to A ?

a) Rs.500

b) Rs.400

c) Rs.600

d) Rs.450

Answer: (b)

Let the C.P. for A be Rs.x, then

$x × 110/100 × 105/100 = 462$

$x = {462 × 100 × 100}/{110 × 105}$ = Rs.400

Using Rule 15,

Here, $r_1 = 10%, r_2$ = 5%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

462 = C.P. for A

$(1 + 10/100)(1 + 5/100)$

C.P. for A = ${462 × 100 × 100}/{110 × 105}$ = Rs.400

Question : 7 [SSC FCI Assistant Grade-III 2013]

A sells an article to B at a gain of 20% and B sells it to C at a gain of 10% and C sells it to D at a gain of 12$1/2$%. If D pays Rs.29.70, A purchased the article for

a) Rs.40

b) Rs.30

c) Rs.20

d) Rs.10

Answer: (c)

Using Rule 15,

Let C.P. for A be Rs.x

$x × 120/100 × 110/100 × 225/200$ = 29.70

$x = {29.70 × 100 × 100 × 200}/{120 × 110 × 225}$ = Rs.20

Question : 8 [SSC CGL Tier-II 2013]

A sells a suitcase to B at 10% profit. B sells it to C at 30% profit. If C pays Rs.2,860 for it, then the price at which A bought it is

a) Rs.1,000

b) Rs.2,500

c) Rs.2,000

d) Rs.1,600

Answer: (c)

Using Rule 15,

Let the C.P. of the suitcase for A be Rs.x, then

$x × 110/100 × 130/100$ = 2860

$x = {2860 × 100 × 100}/{110 × 130}$ = Rs.2000

Question : 9 [SSC CPO S.I.2007]

A car worth Rs.1,50,000 was sold by X to Y at 5% profit. Y sold the car back to X at 2% loss. In the entire transaction

a) X gained Rs.4,350

b) X lost Rs.3,150

c) X gained Rs.3,150

d) Y lost Rs.4,350

Answer: (c)

SP for Mr. X = 150000 × $105/100$ = Rs.157500

CP for Mr. Y = Rs.157500

Y sells the article to X at a loss of 2%.

SP for Mr. Y = 157500 × $98/100$ = Rs.154350

CP for Mr. X = Rs.154350

Gain of Mr. X = Rs.(157500 - 154350) = Rs.3150

Question : 10 [SSC CGL Prelim 2008]

A piece of land came to a person through three middleman each gaining 20%. If the person purchased the land for Rs.3,45,600 the original cost of the land was

a) Rs.1,00,000

b) Rs.2,00,000

c) Rs.1,75,800

d) Rs.1,50,000

Answer: (b)

Let the original cost of the land be Rs.x

According to the question,

345600 = P$(1+ 20/100)^3$

345600 = P$(6/5)^3 = {216P}/125$

P = ${345600 × 125}/216$ = Rs.200000

IMPORTANT quantitative aptitude EXERCISES

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