Practice Sold at circular path - quantitative aptitude Online Quiz (set-1) For All Competitive Exams

Q-1)   A man purchased an article and sold it to B at a profit of 25% and B sold it to C at a loss of 10% and C paid Rs.675 for it. For how much did A purchase it (in Rs.) ?

(a)

(b)

(c)

(d)

Explanation:

Let the C.P. of A be Rs.x, then

${x × 125}/100 × 90/100$ = 675

$x = {675 × 100 × 100}/{125 × 90}$ = Rs.600

Using Rule 15,

Here, $r_1 = 25%, r_2$ = 10%, (Loss)

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

675 = C.P. for A

$(1 + 25/100)(1 + 10/100)$

C.P. for A = ${675 × 100 × 100}/{125 × 90}$ = Rs.600

Q-2)   A sells an article to B making a profit of 1 5 of his outlay. B sells it to C, gaining 20%. If C sells it for Rs.600 and incurs a loss of 1 6 of his outlay, the cost price of article for A is

(a)

(b)

(c)

(d)

Explanation:

If the C.P. for A be Rs.x, then

$x × (1 +1/5) × 120/100 × (1 - 1/6)$ = 600

$x × 6/5 × 6/5 × 5/6 = 600$

$x = {600 × 5}/6$ = Rs.500

Q-3)   A saleable article passes successively in the hands of three traders. Each trader sold it further at a gain of 25% of the cost price. If the last trader sold it for Rs.250 then what was the cost price for the first trader ?

(a)

(b)

(c)

(d)

Explanation:

Let the actual C.P. be Rs.x

$x × 125/100 × 125/100 × 125/100 = 250$

x = Rs.128

Q-4)   A sells an article to B at a gain of 10%, B sells it to C at a gain of 5%. If C pays Rs.462 for it, what did it cost to A ?

(a)

(b)

(c)

(d)

Explanation:

Let the C.P. for A be Rs.x, then

$x × 110/100 × 105/100 = 462$

$x = {462 × 100 × 100}/{110 × 105}$ = Rs.400

Using Rule 15,

Here, $r_1 = 10%, r_2$ = 5%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

462 = C.P. for A

$(1 + 10/100)(1 + 5/100)$

C.P. for A = ${462 × 100 × 100}/{110 × 105}$ = Rs.400

Q-5)   A sells a bicycle to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs.225/- for it, the cost price of the bicycle for A is :

(a)

(b)

(c)

(d)

Explanation:

Let the cost price of the bicycle for A be Rs.x

Cost price for B = selling price for A = 1.20x

Cost price for C = selling price for B = (1.25) (1.20x) = 1.5x

But 1.5x = 225 ⇒ x = $225/1.5$ = Rs.150

The cost price of the bicycle for A = Rs.150

Using Rule 15,
If A sells an article to B at a profit (loss) of $r_1$% and B sells the same article to C at a profit (loss) of $r_2$% then the cost price of article for C will be given by
C.P of article for C
= C.P. of A × $({1 ± r_1}/100)({1 ± r_2}/100)$
(Positive and negative sign conventions are used for profit and loss.)

Here, $r_1= 20%, r_2$ = 25%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

225 = C.P. for A

$(1 + 20/100)(1 + 25/100)$

C.P. for A = ${225 × 100 × 100}/{120 × 125}$ = Rs.150

Q-6)   A sells a cycle to B at a profit of 10%, B sells to C at a profit of 20%. If C pays Rs.264 for it, how much did A pay for it?

(a)

(b)

(c)

(d)

Explanation:

Let the C.P. of A be Rs.x, then

$x × 110/100 × 120/100 = 264$

$x = {264 × 100 × 100}/{110 × 120}$ = Rs.200

Using Rule 15,

Here, $r_1 = 10%, r_2$ = 20%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

264 = C.P. for A

$(1 + 10/100)(1 + 20/100)$

C.P. for A = ${264 × 100 × 100}/{110 × 120}$ = Rs.200

Q-7)   A sells an article to B at a gain of 20% and B sells it to C at a gain of 10% and C sells it to D at a gain of 12$1/2$%. If D pays Rs.29.70, A purchased the article for

(a)

(b)

(c)

(d)

Explanation:

Using Rule 15,

Let C.P. for A be Rs.x

$x × 120/100 × 110/100 × 225/200$ = 29.70

$x = {29.70 × 100 × 100 × 200}/{120 × 110 × 225}$ = Rs.20

Q-8)   A sells a cycle to B at a profit of 5% and B sells it to C at a profit of 10%. If C pays Rs.2310 for it, the cost price of A is

(a)

(b)

(c)

(d)

Explanation:

Let the C.P. for A be Rs.x, then

$x × 105/100 × 110/100$ = 2310

$x = {2310 × 100 × 100}/{105 × 110}$ = Rs.2000

Using Rule 15,

Here, $r_1 = 5%, r_2$ = 10%

C.P. for C = C.P. for A

$(1 + r_1/100)(1 + r_2/100)$

2310 = C.P. for A

$(1 + 5/100)(1 + 10/100)$

C.P. for A = ${2310 × 100 × 100}/{105 × 110}$ = 2000

Q-9)   A sells a suitcase to B at 10% profit. B sells it to C at 30% profit. If C pays Rs.2,860 for it, then the price at which A bought it is

(a)

(b)

(c)

(d)

Explanation:

Using Rule 15,

Let the C.P. of the suitcase for A be Rs.x, then

$x × 110/100 × 130/100$ = 2860

$x = {2860 × 100 × 100}/{110 × 130}$ = Rs.2000

Q-10)   A sells an article to B at a gain of 10%. B sells it to C at a gain of 7$1/2$%. C disposes of it at a loss of 25%. If the prime cost to manufacturer A was Rs.3200 then the price obtained by C is

(a)

(b)

(c)

(d)

Explanation:

Using Rule 15,

Price obtained by C

= $3200 × 110/100 × 215/200 × 75/100$ = Rs.2838