Model 3 Opening both taps and leaks Practice Questions Answers Test with Solutions & More Shortcuts

Question : 21 [SSC CGL Prelim 2008]

A tank has a leak which would empty the completely filled tank in 10 hours. If the tank is full of water and a tap is opened which admits 4 litres of water per minute in the tank, the leak takes 15 hours to empty the tank. How many litres of water does the tank hold ?

a) 7200 L

b) 1200 L

c) 2400 L

d) 4500 L

Answer: (a)

Let the capacity of the tank = x litres

According to the question,

Quantity of water emptied by the leak in 1 hour = $x/10$ litres

Qunatity of water filled by the tap in 1 hour = 240 litres

According to the question,

$x/10 - x/15$ = 240

${3x - 2x}/30 = 240$

$x/30$ = 240

$x$ = 240 × 30 = 7200 litres

Question : 22 [SSC GL Tier-I 2013]

Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes, P is turned off. In how many more minutes will Q fill the cistern ?

a) 8$1/4$ minutes

b) 8 minutes

c) 7 minutes

d) 7$1/2$ minutes

Answer: (a)

Using Rule 1,
Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?
Required time = $({xy}/{x + y})$ hrs

Part of the tank filled in 3 minutes by pipes P and Q

= $3(1/12 + 1/15)$

= $3({5 + 4}/60) = {3 × 9}/60 = 9/20$

So, Remaining part

= 1– $9/20 = 11/20$

Time taken by Q

= $11/20 × 15 = 33/4 = 8{1}/4$ minutes

Question : 23 [SSC SO 2007]

A tank can be filled with water by two pipes A and B together in 36 minutes. If the pipe B was stopped after 30 minutes, the tank is filled in 40 minutes. The pipe B can alone fill the tank in

a) 90 minutes

b) 75 minutes

c) 45 minutes

d) 60 minutes

Answer: (a)

Let the pipe B fill the tank in x minutes.

Part of the tank filled by pipes A and B in 1 minute = $1/36$

Part of the tank filled by pipe A in 1 minute

= $1/36 - 1/x$

According to the question,

30 × $1/x + 40(1/36 - 1/x) = 1$

$30/x + 10/9 - 40/x$ = 1

$40/x - 30/x = 10/9 - 1$

$10/x = 1/9 ⇒ x = 90$ minutes

Question : 24 [SSC Delhi Police S.I.2012]

Two pipes A and B can fill a tank in 6 hours and 8 hours respectively. If both the pipes are opened together, then after how many hours should B be closed so that the tank is full in 4 hours?

a) $8/3$ hrs

b) 2 hrs

c) $2/3$ hrs

d) 1hrs

Answer: (a)

Part of the tank filled in 4 hours by pipe A = $4/6 = 2/3$

Remaining part = ${1 - 2}/3 = 1/3$

Time taken by pipe B in filling $1/3$ part = $8/3$ hours

Using Rule 8,

Here, x = 6, y = 8, t = 4

Required time = $[y(1 –{t/x})]$ hours

= $[8(1 - 4/6)]$ hours = $8/3$ hours

Question : 25 [SSC CGL Tier-II 2016]

A water tap fills a tub in ‘p’ hours and a sink at the bottom empties it in ‘q’ hours. If p < q and both tap and sink are open, the tank is filled in ‘r’ hours; then

a) r = p - q

b) r = p + q

c) $1/r = 1/p + 1/q$

d) $1/r = 1/p - 1/q$

Answer: (d)

Since, P < q,

On opening pipe and sink together,

Part of the tub filled in 1 hour

= $1/P - 1/q$

Clearly, $1/P - 1/q = 1/r$

IMPORTANT quantitative aptitude EXERCISES

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