Model 3 Opening both taps and leaks Practice Questions Answers Test with Solutions & More Shortcuts
pipes & cisterns PRACTICE TEST [3 - EXERCISES]
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
Question : 6
Pipe A can fill a tank in 4 hours and pipe B can fill it in 6 hours. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
a) 4$2/3$
b) 3$1/4$
c) 4$1/2$
d) 3$1/2$
Answer »Answer: (a)
Using Rule 1,Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?Required time = $({xy}/{x + y})$ hrs
Part of tank filled in first two hours
= $1/4 + 1/6 = {3 + 2}/12 = 5/12$
Part of tank filled in first 4 hours
= $10/12 = 5/6$
Remaining part = $1 - 5/6 = 1/6$
This remaining part willl be filled by pipe A.
Time taken by pipe A
= $1/6 × 4 = 2/3$ hour
Total time = 4 + $2/3 = 4{2}/3$ hours
Question : 7 [SSC SO 2005]
A tank is fitted with two taps. The first tap can fill the tank completely in 45 minutes and the second tap can empty the full tank in one hour. If both the taps are opened alternately for one minute, then in how many hours the empty tank will be filled completely ?
a) 5 hours 53 minutes
b) 4 hours 48 minutes
c) 2 hours 55 minutes
d) 3 hours 40 minutes
Answer »Answer: (a)
Using Rule 7,
Part of the tank filled in one minute
= $1/45 - 1/60 = {4 - 3}/180 = 1/180$
Since, $1/180$ part is filled in 1 minute
$1 - 1/45 = 44/45$ part is filled in
${2 × 180 × 44}/45$ = 352 minutes
i.e. 5 hours 52 minutes
Remaining $1/45$ part will be filled in 1 minute.
Total time taken = 5 hours 53 minutes
Question : 8 [SSC CGL Tier-I 2014]
A pipe can fill a cistern in 9 hours. Due to a leak in its bottom, the cistern fills up in 10 hours. If the cistern is full, in how much time will it be emptied by the leak ?
a) 100 hours
b) 90 hours
c) 70 hours
d) 80 hours
Answer »Answer: (b)
Using Rule 7,
Part of the tank emptied by the leak in 1 hour
= $1/9 - 1/10 = {10 - 9}/90 = 1/90$
Required time = 90 hours
Question : 9 [SSC FCI Assistant Grade-III 2012]
A cistern is normally filled in 8 hours but takes another 2 hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in :
a) 40 hours
b) 25 hours
c) 16 hours
d) 20 hours
Answer »Answer: (a)
Using Rule 7,
Part emptied by the leak in 1 hour
= $1/8 - 1/10 = {5 - 4}/40 = 1/40$
The leak will empty the cistern in 40 hours.
Question : 10 [SSC CHSL 2015]
A pipe can fill a tank in 24 hrs. Due to a leakage in the bottom, it is filled in 36 hrs. If the tank is half full, how much time will the leak take to empty the tank?
a) 24 hrs
b) 36 hrs
c) 48 hrs
d) 72 hrs
Answer »Answer: (b)
Using Rule 7,
Part of tank emptied by leak in an hour
= $1/36 - 1/24 = {2 - 3}/72 = {–1}/72$
Time taken in emptying the full tank
= 72 hours
Required time = 36 hours
IMPORTANT quantitative aptitude EXERCISES
Model 3 Opening both taps and leaks Shortcuts »
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