Model 2 Filling tank by parts or fractions Practice Questions Answers Test with Solutions & More Shortcuts
pipes & cisterns PRACTICE TEST [3 - EXERCISES]
Model 1 Basic Pipes & Cisterns problems
Model 2 Filling tank by parts or fractions
Model 3 Opening both taps and leaks
Question : 1
Pipe A can fill the tank 3 times faster in comparison to pipe B. It takes 36 minutes for pipe A and B to fill the tank together. How much time will pipe B alone take to fill the tank?
a) 100 minutes
b) 124 minutes
c) 134 minutes
d) 144 minutes
e) 154 minutes
Answer »Answer: (d)
Let the time taken by pipe B be x minutes
So, the time taken by pipe A = x/3 minutes
Thus, 1/3 + 3/x = 1/36
⇒ 4/x = 1/36
⇒ x = 4×36
⇒ x = 144 minutes
Question : 2
20 buckets can fill a tank when the capacity of each bucket is 12 liters. If the capacity of each bucket is 10 liters, find the number of buckets required to fill the tank.
a) 30 buckets
b) 34 buckets
c) 24 buckets
d) 27 buckets
Answer »Answer: (c)
Capacity of each bucket = 12 liters
20 buckets can fill the tank. So, capacity of tank = 20 * 12= 240 liters
New capacity of bucket = 10 liters
So, 10 liters can be poured into the tank by one bucket
240 liters will be poured by $1/10$ x 240 = 24 buckets
Question : 3 [SSC CHSL 2012]
If $3/5$ th of a cistern is filled in 1 minute, the time needed to fill the rest is
a) 36 sec
b) 40 sec
c) 24 sec
d) 30 sec
Answer »Answer: (b)
Time taken to fill the $3/5$ of the cistern = 60 seconds
Time taken in filling $2/5$ part
= ${60 × 5}/3 × 2/5$ = 40 seconds
Question : 4 [SSC MTS 2013]
There are two pumps to fill a tank with water. First pump can fill the empty tank in 8 hours, while the second in 10 hours. If both the pumps are opened at the same time and kept open for 4 hours, the part of tank that will be filled up is :
a) $2/5$
b) $9/10$
c) $1/54$
d) $1/10$
Answer »Answer: (b)
Using Rule 1
Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?Required time = $({xy}/{x + y})$ hrs
Part of the tank filled in an hour by both pumps
= $1/8 + 1/10 = {5 + 4}/40 = 9/40$
Part of the tank filled in 4 hours
= ${4 × 9}/40 = 9/10$
Question : 5 [SSC CPO 2011]
Pipes P and Q can fill a tank in 10 and 12 hours respectively and C can empty it in 6 hours. If all the three are opened at 7 a.m., at what time will one-fourth of the tank be filled ?
a) 11 p.m.
b) 10 a.m.
c) 11 a.m.
d) 10 p.m.
Answer »Answer: (d)
Using Rule 2,If x, y, z, ........... all taps are opened together then, the time required to fill/empty the tank will be:$1/x ± 1/y ± 1/z ± ... = 1/T$Where T, is the required timeNote: Positive result shows that the tank is filling and Negative result shows that the tank is getting empty.
Part of tank filled in 1 hour when all three pipes are opened
= $1/10 + 1/12 - 1/6= {6 + 5 - 10}/60 = 1/60$
The tank will be filled in 60 hours.
One fourth of the tank will be filled in 15 hours $[1/4 × 60]$
i.e. the tank will be filled at 10 p.m.
IMPORTANT quantitative aptitude EXERCISES
Model 2 Filling tank by parts or fractions Shortcuts »
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