Model 3 Opening both taps and leaks Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 3 EXERCISES

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The following question based on pipes & cisterns topic of quantitative aptitude

Questions : A tank can be filled with water by two pipes A and B together in 36 minutes. If the pipe B was stopped after 30 minutes, the tank is filled in 40 minutes. The pipe B can alone fill the tank in

(a) 90 minutes

(b) 75 minutes

(c) 45 minutes

(d) 60 minutes

The correct answers to the above question in:

Answer: (a)

Let the pipe B fill the tank in x minutes.

Part of the tank filled by pipes A and B in 1 minute = $1/36$

Part of the tank filled by pipe A in 1 minute

= $1/36 - 1/x$

According to the question,

30 × $1/x + 40(1/36 - 1/x) = 1$

$30/x + 10/9 - 40/x$ = 1

$40/x - 30/x = 10/9 - 1$

$10/x = 1/9 ⇒ x = 90$ minutes

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Read more opening both taps and leaks Based Quantitative Aptitude Questions and Answers

Question : 1

Two pipes A and B can fill a tank in 6 hours and 8 hours respectively. If both the pipes are opened together, then after how many hours should B be closed so that the tank is full in 4 hours?

a) $8/3$ hrs

b) 2 hrs

c) $2/3$ hrs

d) 1hrs

Answer: (a)

Part of the tank filled in 4 hours by pipe A = $4/6 = 2/3$

Remaining part = ${1 - 2}/3 = 1/3$

Time taken by pipe B in filling $1/3$ part = $8/3$ hours

Using Rule 8,

Here, x = 6, y = 8, t = 4

Required time = $[y(1 –{t/x})]$ hours

= $[8(1 - 4/6)]$ hours = $8/3$ hours

Question : 2

A water tap fills a tub in ‘p’ hours and a sink at the bottom empties it in ‘q’ hours. If p < q and both tap and sink are open, the tank is filled in ‘r’ hours; then

a) r = p - q

b) r = p + q

c) $1/r = 1/p + 1/q$

d) $1/r = 1/p - 1/q$

Answer: (d)

Since, P < q,

On opening pipe and sink together,

Part of the tub filled in 1 hour

= $1/P - 1/q$

Clearly, $1/P - 1/q = 1/r$

Question : 3

A tank can be filled by two pipes in 20 minutes and 30 minutes respectively. When the tank was empty, the two pipes were opened. After some time, the first pipe was stopped and the tank was filled in 18 minutes. After how much time of the start was the first pipe stopped?

a) 12 minutes

b) 10 minutes

c) 5 minutes

d) 8 minutes

Answer: (d)

Let the first pipe be closed after x minutes

$x/20 + 18/30$ = 1

$x/20 = 1 - 18/30 = 1 - 3/5 = 2/5$

$x = 2/5 × 20$ = 8 minutes

Using Rule 8,
Two taps A and B can fill a tank in x hours and y hours respectively. If both the pipes are opened together, then the time after which pipe B should be closed so that the tank is full in t hours
Required time = $[y(1 –{t/x})]$ hours

Here, x = 20, y = 30, t = 18

Required time = $[x(1 –{t/y})]$

[Since, first pipe is closed]

= $[20(1 - 18/30)] = 20 × 12/30$ = 8 minutes

Question : 4

Two pipes, P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes, P is turned off. In how many more minutes will Q fill the cistern ?

a) 8$1/4$ minutes

b) 8 minutes

c) 7 minutes

d) 7$1/2$ minutes

Answer: (a)

Using Rule 1,
Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?
Required time = $({xy}/{x + y})$ hrs

Part of the tank filled in 3 minutes by pipes P and Q

= $3(1/12 + 1/15)$

= $3({5 + 4}/60) = {3 × 9}/60 = 9/20$

So, Remaining part

= 1– $9/20 = 11/20$

Time taken by Q

= $11/20 × 15 = 33/4 = 8{1}/4$ minutes

Question : 5

A tank has a leak which would empty the completely filled tank in 10 hours. If the tank is full of water and a tap is opened which admits 4 litres of water per minute in the tank, the leak takes 15 hours to empty the tank. How many litres of water does the tank hold ?

a) 7200 L

b) 1200 L

c) 2400 L

d) 4500 L

Answer: (a)

Let the capacity of the tank = x litres

According to the question,

Quantity of water emptied by the leak in 1 hour = $x/10$ litres

Qunatity of water filled by the tap in 1 hour = 240 litres

According to the question,

$x/10 - x/15$ = 240

${3x - 2x}/30 = 240$

$x/30$ = 240

$x$ = 240 × 30 = 7200 litres

Question : 6

Three pipes A, B and C can fill a tank in 6 hours. After working together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is

a) 16

b) 14

c) 10

d) 12

Answer: (b)

A, B and C together fill the tank in 6 hours.

Part of the tank filled in 1 hour by (A + B + C) = $1/6$

Part of the tank filled in 2 hours by all three pipes

= $2/6 = 1/3$

Remaining empty part

= $1 - 1/3 = 2/3$

This $2/3$ part is filled by (A + B).

Time taken by (A + B) to fill the fully empty tank

= ${7 × 3}/2 = 21/2$ hours

Part of tank filled by C in 1 hour

= $1/6 - 2/21 = {7 - 4}/42 = 3/42 = 1/14$

∴ Required time = 14 hours.

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