pipes & cisterns Topic-wise Short Notes, Solutions, Methods, Tips, Tricks & Techniques to Solve Problems

Pipes and Cisterns - Basic Formulas, Shortcuts, Rules, Tricks & Tips - Quantitative Aptitude

Useful For All Competitive Exams Like UPSC, SSC, BANK & RAILWAY

Posted By Careericons Team

Introduction to Pipes and Cisterns:

Pipe and cistern or tank problems are similar to time and work problems. These problems generally consist of a cistern (tank) to which one or more pipes fill the cistern or empty the cistern may be thought of as completing a job.

These problems of pipes and cisterns can be solved by using the same method used in time and work. And we changes our formulae according to the requirement of the pipes and cisterns.

  1. A pipe connected with a tank or a cistern that fill the tank is known as inlet.
  2. A pipe connected with a tank that empty it is known as outlet.

Pipes and Cisterns are Extension of the Concept of Time & Work:

Here's how, Problems related to Pipes and Cisterns are almost the same as those of Time and Work. Statement ‘pipes A and B can fill a tank in 2 hours and 3 hours working individually’ is similar to the statement ‘A and B can do a work in 2 hours and 3 hours respectively working individually’.

If a pipe fills a tank in 3 hours, then the pipe fills $1/3$ rd of the same tank in 1 hour.

The only difference with the pipes and cisterns problems is that there are inlets as well as outlets. Inlet is a pipe connected with a tank (or a cistern or a reservoir) that fills it. Outlet is a pipe connected with a tank (or a cistern or a reservoir) that empties it.

Hence, if we consider filling the tank by inlet as positive work, then empting the tank by outlet will be considered as negative work.

Lets workout some solved examples based on Pipes & Cictens problems which will help you to understand more about the concept.

Solved Example 1:

A tank is three-fourths full. Pipe A can fill the tank in 16 minutes. Pipe B can empty it in 12 minutes. If both pipes are open, how long will it take to empty the tank?

Solution Ex1: Pipe A can fill $1/16$ of the tank in 1 minute.

Pipe B can empty $1/12$ of the tank in 1 minute.

In 1 minute $1/{12} - 1/{16} = 1/{48}$ of the tank is emptied.

It would take 48 minutes to empty the whole tank.

However, the tank is only $3/4$ full.

So, it will take $3/4$ × 48 = 36 minutes to empty the tank.


Solved Example 2:

A certain tank can be filled by pipe A in 8 minutes. Pipe B can empty the tank in 12 minutes. If both pipes are open, how long will it take to fill or empty the tank?

Solution Ex2: Pipe A fills $1/8$ of the tank in 1 minute.

Pipe B empties $1/12$ of the tank in 1 minute.

Since $1/8$ is greater than $1/12$ , the tank will ultimately be filled.

In one minute $1/8 - 1/12 = 1/24$ of the tank is actually filled.

Therefore, the tank will be completely filled in 24 minutes.


Solved Example 3:

Two pipes can fill a tank with water in 15 and 12 hours respectively, and a third pipe can empty it in 4 hours. If the pipes be opened in order, at 8, 9 and 11 a.m. respectively, the tank will be emptied at ?

Solution Ex3: Part filled by pipe A from 8 a.m. to 11 a.m. = $3/15$ = $1/5$

Part filled by pipe B from 9 a.m. to 11 a.m. = $2/12$ = $1/6$

Part filled till 11 a.m.

= $1/5 + 1/6$

= ${6+5}/30$ = $11/30$

At 11 a.m. pipe C is opened to empty it.

∴ Part of tank emptied in 1 hour

= $1/4 - 1/15 - 1/12$

= ${15 - 4 - 5}/60$

= $6/60$ = $1/10$

∴ $11/30$ part will be emptied in $11/30 ×10/1 30$

= $11/3$ hours

i.e. in 3 hours 40 minutes or i.e., at 11.40 a.m.


Most Important 6 Key Points To Solve All Types of Pipes & Cisterns Aptitude Problems:

Hint 1. If a pipe can fill a tank in x hours, then the part filled in 1 hour = $1/x$

Hint 2. If a pipe can empty a tank in y hours, then the part of the full tank emptied in 1 hour= $1/y$

Hint 3. If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours (y > x), then the net part filled in 1 hour, when both the pipes are opened = $(1/x - 1/y) = {y-x}/{xy}$

Time taken to fill the tank = ${xy}/{y-x}$

Hint 4. If a pipe can fill a tank in x hours and another pipe can fill the same tank in y hours, the part of the tank filled in 1 hour when both pipes are opened simultaneously $(1/x + 1/y) = {x+y}/{xy}$

Time taken to fill completely the tank when both pipes are open simultaneously = ${xy}/{x+y}$

Hint 5. If three pipes can fill a tank separately in x, y and z h respectively, then time taken to fill the tank by working together = ${xyz}/{xy + yz + zx}$

Hint 6. If a pipe fills a tank in x hours and another fills the same tank in y hours, but a third pipe empties the full tank in z hours and all of them are opened together, the net part filled in 1 hour = ${xy}/{y-x}$

Time taken to fill the tank = ${xyz}/{yz + xz - xy}$ hours


"9" - Important Aptitude Rules, Formulas & Quick Tricks to Solve Pipes and Cisterns Based Aptitude Problems

In this list of rules, you will get an idea that How to solve all different types & kinds of Pipes and Cisterns based aptitude problems asked in various competitive exams like UPSC, SSC, Bank, and Railway examinations at all levels.

By using this method, you can able to solve all problems from basic level to advanced level of questions asked based on Pipes and Cisterns in a faster approch.

Let's discuss the rules one by one with all Pipes and Cisterns Rules & Formulas with examples,

RULE 1 :

Two taps 'A' and 'B' can fill a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then how much time it will take to fill the tank?

Required time = $({xy}/{x + y})$ hrs


RULE 2 :

If x, y, z, ........... all taps are opened together then, the time required to fill/empty the tank will be:

$1/x ± 1/y ± 1/z ± ... = 1/T$

Where T, is the required time
Note: Positive result shows that the tank is filling and Negative result shows that the tank is getting empty.,


RULE 3 :

Two taps can fill a tank in 'x' and 'y' hours respectively. If both the taps are opened together and 1st tap is closed before 'm' hours of filling the tank, then in how much time the tank will be filled?

Required time = ${(x + m)y}/{(x + y)}$ hrs

If 2nd tap is closed before 'm' hours then,

Required time = ${(y + m)x}/{(x + y)}$ hrs


RULE 4 :

If a pipe fills a tank in 'x' hours but it takes 't' more hours to fill it due to leakage in tank. If tank is filled completely, then in how many hours it will be empty? [due to leakage outlet]

Required time = ${x(x + t)}/t$


RULE 5 :

Amount of water released or filled = Rate × time.


RULE 6 :

Two taps 'A; and 'B' can empty a tank in 'x' hours and 'y' hours respectively. If both the taps are opened together, then time taken to empty the tank will be

Required time = $({xy}/{x + y})$ hrs


RULE 7 :

A tap 'A' can fill a tank in 'x' hours and 'B' can empty the tank in 'y' hours. Then

(a) time taken to fill the tank
when both are opened = $({xy}/{x - y})$ : x > y

(b) time taken to empty the tank
when both are opened = $({xy}/{y- x})$ : y > x


RULE 8 :

Two taps A and B can fill a tank in x hours and y hours respectively. If both the pipes are opened together, then the time after which pipe B should be closed so that the tank is full in t hours

Required time = $[y(1 –{t/x})]$ hours


RULE 9 :

If pipes A & B can fill a tank in time x, B & C in time y and C & A in time z, then the time required/taken to fill the tank by

(i) (A + B + C) together = ${2xyz}/{xy + yz + zx}$

(ii) A alone = ${2xyz}/{xy + yz - zx}$

(iii) B alone = ${2xyz}/{yz + zx - xy}$

(iv) C alone = ${2xyz}/{zx + xy - yz }$


3 - Types of Pipes and Cisterns Based Aptitude Questions and Answers Practise Test With Online Quiz

Click the below links & Learn the specific model from Pipes and Cisterns problems that you have to practice for upcoming examination


Refer: Get all Topic-wsie Quantitative aptitude problems for upcoming competitive exams

pipes & cisterns MCQ QUESTION & ANSWER EXERCISE
pipes & cisterns Shortcuts and Techniques with Examples

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