model 2 net increase or decrease in % Practice Questions Answers Test with Solutions & More Shortcuts
percentage PRACTICE TEST [11 - EXERCISES]
model 1 simple percentage questions
model 2 net increase or decrease in %
model 3 reducing & exceeding prices
model 4 x & y comparison
model 5 income & expenditure
model 6 consumption & remaining
model 7 marks scored in examinations
Model 8 population based
model 9 voters & election
model 10 percentage with allegations & mixture
model 11 percentage with ratios
Question : 16 [SSC CGL Prelim 2002]
A number is increased by 20% and then it is decreased by 10%. Find the net increase or decrease per cent.
a) 10% decrease
b) 8% decrease
c) 8% increase
d) 10% increase
Answer »Answer: (c)
Using Rule 4,
Net % change
= $(A + B + {AB}/100)$%
Here, A = 20%, B = – 10%
Net % change = $20 - 10 - 200/100$
= 10 – 2= 8%
+ ve sign shows increase
Question : 17 [SSC Delhi Police 2012]
The numerator of a fraction is increased by 20% and denominator is decreased by 20%. The value of the fraction becomes $4/5$. The original fraction is
a) $8/15$
b) $4/5$
c) $7/11$
d) $2/3$
Answer »Answer: (a)
Original fraction = $x/y$
= ${120/100x}/{y × 80/100} = 4/5$
= ${120x}/{80y} = 4/5$ ⇒ ${6x}/{4y} = 4/5$
= $x/y = 4/5 × 4/6 = 8/15$
Question : 18 [SSC CPO S.I.2003]
The price of an article was decreased by 10% and again reduced by 10%. By what per cent should the price have been reduced once, in order to produce the same effect as these two successive reductions ?
a) 19%
b) 25%
c) 20%
d) 15%
Answer »Answer: (a)
Using Rule 6,
If a number is first decreased by a% and then by b%, then net decrease per cent is $(-a -b + {ab}/100)$% (–ve sign for decrease)
A single equivalent reduction to reduction series of x%, y%
= $(x + y - {xy}/100)$%
=$(10 + 10 - {10 × 10}/100)$%
=(20 - 1) = 19%
Question : 19 [SSC CPO SI 2016]
The price of an edible oil is increased by 25%. To maintain the budget, Sushma reduces the consumption of this oil by 20%. The increase in expenditure due to this edible oil is:
a) 1
b) 3
c) 2
d) 0
Answer »Answer: (d)
Cost of edible oil = 100 per kg.
Consumption = 1 kg.
Again, New price = 125 per kg.
Consumption = 0.8 kg.
Expenditure = Rs.(125 × 0.8) = Rs.100
OR
Percentage effect = $(x + y + {xy}/100)%$
=$(25 - 20 - {25 × 20}/100)$% = 0%
Question : 20 [SSC CPO S.I.2004]
A number reduced by 25% becomes 225. What per cent should it be increased so that it becomes 375?
a) 30%
b) 75%
c) 35%
d) 25%
Answer »Answer: (d)
Clearly, 75% of the number = 225
Number = ${225 × 100}/75$ = 300
Again, 125% of 300 = 375
Hence, the number should be increased by 25%
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model 2 net increase or decrease in % Shortcuts »
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Click to Start..percentage Shortcuts and Techniques with Examples
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model 1 simple percentage questions
Defination & Shortcuts … -
model 2 net increase or decrease in %
Defination & Shortcuts … -
model 3 reducing & exceeding prices
Defination & Shortcuts … -
model 4 x & y comparison
Defination & Shortcuts … -
model 5 income & expenditure
Defination & Shortcuts … -
model 6 consumption & remaining
Defination & Shortcuts … -
model 7 marks scored in examinations
Defination & Shortcuts … -
Model 8 population based
Defination & Shortcuts … -
model 9 voters & election
Defination & Shortcuts … -
model 10 percentage with allegations & mixture
Defination & Shortcuts … -
model 11 percentage with ratios
Defination & Shortcuts …
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