find distance only Practice Questions Answers Test with Solutions & More Shortcuts

direction & distance sense test PRACTICE TEST [15 - EXERCISES]

find directions only

find distance only

find both direction & distance

find directions only section 2

find directions only section 3

find directions only section 4

find directions only section 5

find directions only section 6

find distance only section 2

find distance only section 3

find distance only section 4

find distance only section 5

find distance only section 6

find both direction & distance section 2

find both direction & distance section 3

Question : 16 [M.A.T. 1999]

X and Y start moving towards each other from two places 200 m apart. After walking 60 m, Y turns left and goes 20 m, then he turns right and goes 40 m. He then turns right again and comes back to the road on which he had started walking. If X and Y walk with the same speed, what is the distance between then now?

a) 20 m

b) 30 m

c) 40 m

d) 50 m

Shortcut »

Answer: (c)

Clearly, Y moves 60 m from Q up to A, then 20 m up to B, 40 m up to C and then up to D.

So, AD = BC = 40 m. QD = (60 + 40) m = 100 m.

Since X and Y travel in the same time i.e. (60 + 20 + 40 + 20) m = 140 m.

So, X travels 140 m up to A.

Therefore, Distance between X and Y = AD = (100 - 60) m = 40 m.

Directions :
Study the information given below carefully and answer the questions given below: A, B, C, D, E, F, G, H and I are nine houses. C is 2 km east of B. A is 1 km north of B and H is 2 km South of A. G is 1 km west of H while D is 3 km east of G and F is 2 km north of G. I is situated just in middle of B and C while E is just in middle of H and D.

[M.A.T. 2003]

Question : 17

Distance between E and G is

a) 1 km

b) 1.5 km

c) 2 km

d) 5 km

Shortcut »

Answer: (c)

Since E lies in middle of H and D, so HE = ED. But HD = 2 km.

So, HE = ED = 1 km.

Therefore, Required distance = GE = GH + HE

= (1 + 1) km = 2 km.

Question : 18

Distance between E and I is

a) 1 km

b) 2 km

c) 3 km

d) 4 km

Shortcut »

Answer: (a)

I lies in middle of B and C.

So, BI = IC. But bC = 2 km.

Then, BI = IC = 1 km.

I lies directly above E.

Therefore, Required distance = EI = HB = 1 km.

Question : 19

Distance between A and F is

a) 1 km

b) 1.41 km

c) 2 km

d) 3 km

Shortcut »

Answer: (a)

Since GF = AH = 2 km, so F and A lie in the same line.

Therefore, Required distance = AF = GH = 1 km.

Directions :
Study the information given below carefully and answer the questions that follow: On a playing ground, Dinesh, Kunal, Nitin, Atul and Prashant are standing as described below facing the North.

    (i) Kunal is 40 metres to the right of Atul.
    (ii) Dinesh is 60 metres to the south of Kunal.
    (iii) Nitin is 25 metres to the west of Atul.
    (iv) Prashant is 90 metres to the north of Dinesh.
[NMAT, 2005]

Question : 20

If a boy walks from Nitin, meets Atul followed by Kunal, Dinesh and then Prashant, how many metres has he walked if he has travelled the straight distance all through?

a) 155 metres

b) 185 metres

c) 215 metres

d) 245 metres

e) None of these

Shortcut »

Answer: (c)

Required distance = NA + AK + KD + DP

= (25 + 40 + 60 + 90) m = 215 m.

IMPORTANT verbal reasoning EXERCISES

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