find distance only Practice Questions Answers Test with Solutions & More Shortcuts

Question : 86

Rimpy, on her morning walk, starting from home she walks to the North for 250 m, then she turns to her right and travels 20 m and then she again turns to the right and drives straight another 250 m. How much distance has she now to cover to go back to her home?

a) 4 m

b) 25 m

c) 20 m

d) 40 m

e) 30 m

Answer: (c)

Question : 87 [SSC CGL Tier-I 2016]

Ram walks 3 km towards East and takes a left turn and walks for one km before he turns left and walks 2 km to take another left turn to walk for another one km. How many km is he away from his starting point?

a) 2kms

b) 4kms

c) 1km

d) 3kms

Answer: (c)

direction-and-distance-verbal-reasoning

Question : 88

A man walks 1 km towards East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km, after this he turns to North and walks 9 km. Now, how far is he from his starting point?

a) 4 km

b) 7 km

c) 3 km

d) 5 km

Answer: (d)

direction-and-distance

The movements of the man are as shown in Fig.

(A to B, B to C, C to D and D to E)

Clearly, DF = BC = 5 km

EF= (DE- DF) = (9-5) km = 4 km

BF = CD = 2 km

AF = AB + BF = AB + CD = (1 + 2) km = 3 km

∴ Man's distance from starting point A = AE

= $√{AF^2 + EF^2}$ = $√{3^2 + 4^2}$ = $√{25}$ = 5 km

Question : 89

In the given figure. P is 300 km eastward of O and Q is 400 km north of O. R is exactly in the middle of Q and P. The distance between Q and R is

a) 300 km

b) 250 km

c) 250 km

d) 350 km

Answer: (c)

Clearly, PQ = $√{OP^2 + OQ^2}$

= $√{90000 + 160000}$ = 500km

Since, R is the midpoint of PQ, 

So QR = $1/2$ X PQ

= 250 km

Question : 90 [SSC CGL Tier-I 2016]

A girl walks 30 metre towards south, then turning to her right she walks 30 metre, then turning to her left, she walks 20 metre, again she turns to her left and walks 30 metre. How far is she from her initial position?

a) 30 metre

b) 60 metre

c) 20 metre

d) 50 metre

Answer: (d)

direction-and-distance-verbal-reasoning

Required distance = AE

= (30 + 20) metres

= 50 metres

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