find a day without reference day Practice Questions Answers Test with Solutions & More Shortcuts
calendar PRACTICE TEST [4 - EXERCISES]
basic calendar problems
find a day with reference day
find a day without reference day
finding a week on basis of another week
Question : 6
On which dates of April 2012 will a Sunday come?
a) 5, 12, 19, 26
b) 1, 8, 15, 22, 29
c) 3, 10, 17, 24
d) 7, 14, 21, 28
Answer »Answer: (b)
First of all, we have to find the day on 1st April, 2012 1st April 2012 means
(2011 years 3 months and 1 day)
Now, 2000 years have 0 odd days 11 years have
(2 leap years and 9 ordinary years)
= ( 2 × 2 + 9 × 1 ) odd days
= (4 + 9) odd days = 13
= 6 odd days
3 months and 1 day
January | 31 |
February | 29 |
March | 31 |
April | 1 |
= 92 days = 1 odd day
Total number of odd days = ( 6 + 1 ) = 7
⇒ 0 odd day
Hence, it was Sunday on 1st April 2012. (1st Sunday).
Subsequently, Sundays of the month were on 1st, 8th, 15nd, 22nd, and 29th.
Question : 7
What was the day of the week on 28th May 2006?
a) Thursday
b) Friday
c) Saturday
d) Sunday
Answer »Answer: (d)
Question : 8
What was the day of the week on 17th June, 1998?
a) Monday
b) Tuesday
c) Wednesday
d) Thursday
Answer »Answer: (c)
Question : 9
On What dates of April 2001 did Wednesday fall?
a) 1st, 8th, 15th, 22nd, 29th
b) 2nd, 9th, 16th, 23rd, 30th
c) 3rd, 10th, 17th, 24th
d) 4th, 11th, 18th, 25th
Answer »Answer: (d)
Question : 10
What day of the week was on 1st January 2001?
a) Monday
b) Wednesday
c) Sunday
d) Tuesday
Answer »Answer: (a)
1st January 2001 means 2000 complete years + 1 day of January 2001
Number of odd days in 2000 yrs = 0
Number of odd days in January 2001 = 1
Total number of odd days = 0+1 = 1
So, the required day was Monday
IMPORTANT verbal reasoning EXERCISES
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