Model 4 Train Vs Pole/Signal Post/Man Section-Wise Topic Notes With Detailed Explanation And Example Questions

MOST IMPORTANT quantitative aptitude - 6 EXERCISES

Top 10,000+ Aptitude Memory Based Exercises

The following question based on trains topic of quantitative aptitude

Questions : In what time will a 100 metre long train running with a speed of 50 km/hr cross a pillar ?

(a) 72 seconds

(b) 7.2 seconds

(c) 70 seconds

(d) 7.0 seconds

The correct answers to the above question in:

Answer: (b)

Speed of train = 50 kmph

= $({50 × 5}/18)$ m./sec. = $125/9$ m./sec.

Required time = $({100/125}/9)$ seconds

= $({100 × 9}/125)$ = 7.2 seconds

Practice trains (Model 4 Train Vs Pole/Signal Post/Man) Online Quiz

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Read more crossing pole signal post man Based Quantitative Aptitude Questions and Answers

Question : 1

A 120 m long train takes 10 seconds to cross a man standing on a platform. What is the speed of the train ?

a) 10 m/sec.

b) 15 m/sec.

c) 20 m/sec.

d) 12 m/sec.

Answer: (d)

Using Rule 1,

In crossing a man standing on platform, train crosses its own length.

Speed of train = $120/10 = 12$m/s

Question : 2

A train 180 metres long is running at a speed of 90 km/h. How long will it take to pass a post ?

a) 7.8 secs

b) 8 secs

c) 7.2 secs

d) 8.2 secs

Answer: (c)

Using Rule 1,

Speed of train = 90 kmph

= $(90 × 5/18)$ m/sec. = 25 m/sec.

When a train crosses a post, it covers a distance equal to its own length.

Required time = $\text"Distance"/ \text"Speed"$

= $180/25$ = 7.2 seconds

Question : 3

In what time will a train, 60 metre long, running at the rate of 36 km/hr pass a telegraph post ?

a) 8 seconds

b) 7 seconds

c) 6 seconds

d) 9 seconds

Answer: (c)

Speed of train = 36 kmph

= $({36 × 5}/18)$ m./sec. = 10 m./sec.

Required time = $\text"Length of train"/ \text"Speed of train"$

= $60/10$ = 6 seconds

Question : 4

The time taken by a train 160 m long, running at 72 km/hr, in crossing an electric pole is

a) 9 seconds

b) 6 seconds

c) 4 seconds

d) 8 seconds

Answer: (d)

Distance covered in crossing a pole

= Length of train Speed of train = 72 kmph

= $({72 × 5}/18)$ m./sec. = 20 m./sec.

Required time = $160/20$ = 8 seconds

Question : 5

A train 180 m long moving at the speed of 20 m/sec. over-takes a man moving at a speed of 10m/ sec in the same direction. The train passes the man in :

a) 9 sec

b) 18 sec

c) 27 sec

d) 6 sec

Answer: (b)

Using Rule 5,
Let 'a' metre long train is running with the speed 'x' m/s. A man is running in same direction and with the speed 'y' m/s, then time taken by the train to cross the man = $a/{(x - y)}$seconds. And a = (x - y)t

Relative speed of man and train

= 20 - 10 = 10m/sec.

Required time = $180/10$ = 18 seconds

Question : 6

A train passes an electrical pole in 20 seconds and passes a platform 250 m long in 45 seconds. Find the length of the train.

a) 200m

b) 300m

c) 250m

d) 400m

Answer: (a)

Using Rule 1,

If the length of train be x metre, then speed of train

= $x/20 = {x + 250}/45$

$x/4 = {x + 250}/9$

9x = 4x + 1000

9x - 4x = 1000

5x = 1000

x = $1000/5$ = 200 metre

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