Model 6 Efficiency of the worker Practice Questions Answers Test with Solutions & More Shortcuts
time & work PRACTICE TEST [7 - EXERCISES]
Model 1 Basics on Time & Work
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Model 3 Man leaves & joins
Model 4 Working with Man, Woman, Child
Model 5 Split & Fraction of work
Model 6 Efficiency of the worker
Model 7 Working with individual wages
Question : 16 [SSC CGL Tier-I 2011]
A is thrice as good a workman as B and therefore is able to finish a job in 40 days less than B. Working together, they can do it in
a) 15 days
b) 14 days
c) 13 days
d) 20 days
Answer »Answer: (a)
Using Rule 2,
Time taken by A to complete the work = x days
Time taken by B to complete the work = 3x days
So, 3x - x = 2x = 40
x = 20 and 3x = 60
(A + B)’s 1 day’s work
= $1/20 + 1/60 = {3 + 1}/60 = 4/60 = 1/15$
A and B together will complete the work in 15 days.
Question : 17 [SSC CPO S.I.2009]
A is twice as good a workman as B and B is twice as good a workman as C. If A and B can together finish a piece of work in 4 days, then C can do it by himself in
a) 12 days
b) 6 days
c) 8 days
d) 24 days
Answer »Answer: (d)
Using Rule 2,
According to the question,
If A takes x days to complete the work, B will take 2x days and C will take 4x days,
Now, (A + B)'s 1 day’s work = $1/4$
$1/x + 1/{2x} = 1/4 ⇒ {2 + 1}/{2x} = 1/4$
2x = 12 ⇒ x = 6
C will complete the work in 4x i.e. 24 days.
Question : 18 [SSC CHSL 2011]
A can do a certain job in 12 days. B is 60% more efficient than A. To do the same job B alone would take :
a) 7 days
b) 7$1/2$ days
c) 8 days
d) 10 days
Answer »Answer: (b)
Time taken by B
= $12 × 100/160 = 15/2 = 7{1}/2$ days
Using Rule 17,
Here, x = 12, R = 60%
Time taken by B = $x × 100/{100 + R}$ days
= $12 × 100/160$ days
= $15/2$ days = 7$1/2$ days
Question : 19 [SSC CGL Tier-II 2012]
A can do a certain work in 12 days. B is 60% more efficient than A. How many days will B and A together take to do the same job?
a) $60/13$ days
b) $80/13$ days
c) $70/13$ days
d) $75/13$ days
Answer »Answer: (a)
Time taken by B in completing the work
=$12 × 100/160 = 15/2$ days
(A+B)’s 1 day’s work
= $1/12 + 2/15 = {5 + 8}/60 = 13/60$
Hence, the work will be completed in $60/13$ days
Using Rule 17,
Here, x = 12, R = 60%
Time taken by B= $x × 100/{100 + R}$ days
= $12 × 100/160$ days = $15/2$ days
Now using Rule 2,
Time taken by A and B = ${xy}/{x + y}$
= ${12 × {15/2}}/{12 + {15/2}}$
= ${12 × 15}/39 = 60/13$ days
Question : 20 [SSC CGL Prelim 2000]
A and B can do a job together in 12 days. A is 2 times as efficient as B. In how many days can B alone complete the work ?
a) 12 days
b) 18 days
c) 9 days
d) 36 days
Answer »Answer: (d)
Using Rule 2,
If A alone completes the work in x days, B will complete the same in 2x days.
$1/x + 1/{2x} = 1/12$
${2 + 1}/{2x} = 1/12 ⇒ 2x = 36$
B alone will complete the work in 36 days (i.e. 2x ).
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Model 6 Efficiency of the worker Shortcuts »
Click to Read...Model 6 Efficiency of the worker Online Quiz
Click to Start..time & work Shortcuts and Techniques with Examples
-
Model 1 Basics on Time & Work
Defination & Shortcuts … -
Model 2 Formula method ‘M1D1W1 = M2D2W2’
Defination & Shortcuts … -
Model 3 Man leaves & joins
Defination & Shortcuts … -
Model 4 Working with Man, Woman, Child
Defination & Shortcuts … -
Model 5 Split & Fraction of work
Defination & Shortcuts … -
Model 6 Efficiency of the worker
Defination & Shortcuts … -
Model 7 Working with individual wages
Defination & Shortcuts …
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